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sarahc

  • 2 years ago

Let f(x) = 5x + 12. Find f–1(x).

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  1. LordVictorius
    • 2 years ago
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    I was also confused on these.

  2. LordVictorius
    • 2 years ago
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    Switch y and x, y being f(x)

  3. mathsmind
    • 2 years ago
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    is this question about finding the inverse of a function?

  4. LordVictorius
    • 2 years ago
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    Yes.

  5. LordVictorius
    • 2 years ago
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    f-1(x)

  6. LordVictorius
    • 2 years ago
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    f^-1

  7. mathsmind
    • 2 years ago
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    \[y = 5x +12\]

  8. LordVictorius
    • 2 years ago
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    Yes.

  9. LordVictorius
    • 2 years ago
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    x=5y+12

  10. mathsmind
    • 2 years ago
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    \[x = 5y +12\]

  11. LordVictorius
    • 2 years ago
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    Solve for x.

  12. LordVictorius
    • 2 years ago
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    lol

  13. LordVictorius
    • 2 years ago
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    x-12=5y

  14. LordVictorius
    • 2 years ago
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    (x-12)/5=y

  15. mathsmind
    • 2 years ago
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    \[5y = x -12\]

  16. mathsmind
    • 2 years ago
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    \[y = \frac{ x-12 }{ 5 }\rightarrow f ^{-1}(x)=\frac{ x }{ 5 }-\frac{ 12 }{5 }\]

  17. LordVictorius
    • 2 years ago
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    Too late, I got it.

  18. LordVictorius
    • 2 years ago
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    I GTG.

  19. LordVictorius
    • 2 years ago
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    Good luck math.

  20. mathsmind
    • 2 years ago
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    \[y = \frac{ 1 }{ 5 }(x-12)\]

  21. sarahc
    • 2 years ago
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    so it would x-12/5?

  22. mathsmind
    • 2 years ago
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    yup

  23. sarahc
    • 2 years ago
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    thanks!

  24. mathsmind
    • 2 years ago
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    you are welcome but follow the steps

  25. mathsmind
    • 2 years ago
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    so you can do it yourself

  26. mathsmind
    • 2 years ago
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    if you practice the steps i showed you, you'll almost be able to solve any problem of the kind

  27. sarahc
    • 2 years ago
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    okay I did. I got 100 :)

  28. LordVictorius
    • 2 years ago
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    Good for you.

  29. mathsmind
    • 2 years ago
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    did u get 100%

  30. mathsmind
    • 2 years ago
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    good i am happy

  31. LordVictorius
    • 2 years ago
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    Thanks.

  32. mathsmind
    • 2 years ago
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    sorry i was busy in the computer science section

  33. LordVictorius
    • 2 years ago
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    lol

  34. LordVictorius
    • 2 years ago
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    Anyway, can you help me?

  35. LordVictorius
    • 2 years ago
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    I posted my questions.

  36. mathsmind
    • 2 years ago
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    sure what is ur qs? if i know how to solve it?

  37. LordVictorius
    • 2 years ago
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    Bumping now.

  38. mathsmind
    • 2 years ago
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    so where is the question

  39. LordVictorius
    • 2 years ago
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    It should be the third one down.

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