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So you could find the probability of five or less, right?

yes, because it's not continuous. it's a discrete number. i have an example like that in my notes.

because you can do 1-the other

so should i find plug in 6, 5, 4, 3, 2, 1 into the equation and then subtract that answer from 1??

Good idea. Though probably only from 5 down, if you want to include 6 in "6 or more"

so i should do:
p(5)= e^(-2.5) * 2.5^(5) / 5! + p(4)= e^(-2.5) * 2.5^(4) / 4! + ........

I would calculate the prob of 0,1,2,3,4 or 5 events
then 1 - sum = pr(k≥6)

so what i said above ^^^ ???

you left out 0

yeah and included 6. i needa include 0 and exclude 6. everything else seems good though, right?

yes

ok, and for part b do i plug in 15 through 20 for p(x) and then add them up?

with lambda= 2.5*8 =20

wait, what?
do i place that 20 before e and before the ^ (-x) ??

\[(\lambda) ^ - \lambda x) \

@phi @amistre64
can you clarify what i do with the lambda?

for part b
\[ Pr(k)= \frac{\lambda^k e^{-\lambda}}{k!} \]
λ= 20, the number of events in 8 hours

If I did it right, I got Pr(15 to 20) = 0.4542

ok what formula is that? i thought you said we use the poisson one for #4?