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Grazes
 one year ago
Best ResponseYou've already chosen the best response.0n+1 terms, so 11 terms. 6th term, I guess

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0I know the answer, but I was wondering if there was a method to solve it without guessing/inferring what the i1 of \[\left(\begin{matrix}n \\ i1\end{matrix}\right) a ^{n(i1)} b ^{i1}\] is.

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0I copied it verbatim from my textbook oo

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0if you substitute i1 with k, it's right. Mine formula is just so that i can equal the nth term. Your n(th term) would need to be decreased by 1. Just technicalities.

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0errr nevermind. I chose a bad example. You just substitute the given values in this one.
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