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Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0n+1 terms, so 11 terms. 6th term, I guess

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0I know the answer, but I was wondering if there was a method to solve it without guessing/inferring what the i1 of \[\left(\begin{matrix}n \\ i1\end{matrix}\right) a ^{n(i1)} b ^{i1}\] is.

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0I copied it verbatim from my textbook oo

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0if you substitute i1 with k, it's right. Mine formula is just so that i can equal the nth term. Your n(th term) would need to be decreased by 1. Just technicalities.

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0errr nevermind. I chose a bad example. You just substitute the given values in this one.
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