## algebra2sucks Group Title What is the quotient in simplest form? State any restrictions on the variable. x+2/ x-1 divided by x + 4/x^2 + 4x - 5 one year ago one year ago

1. Azteck Group Title

$\frac{ x+2}{ x-1 }\div \frac{ x+4 }{ x^2+4x-5 }=\frac{ x+2 }{ x-1 }\div \frac{ x+4 }{ (x+5)(x-1) }$ $=\frac{ x+2 }{ x-1 }\times \frac{(x+5)(x-1) }{x+4 }$ Simplify it now.

2. algebra2sucks Group Title

(x+2)(x+5)/x+4 ?

3. algebra2sucks Group Title

what are the restrictions?

4. algebra2sucks Group Title

you there @Azteck

5. Azteck Group Title

What can't x equal to?

6. Azteck Group Title

What number do you prevent x to be so that the denominator of the fraction does not become undefined?

7. Azteck Group Title

$\dfrac{(x+2)(x+5)}{x+4}$ What can't x be???

8. Azteck Group Title

@algebra2sucks

9. algebra2sucks Group Title

1,-4,-5?

10. Azteck Group Title

Dude, if x=1, will there be a value coming out from that fraction there?

11. Azteck Group Title

I'm not so sure, but I reckon they're asking you for restrictions after you simplify the quotient.

12. Azteck Group Title

Because questions don't ask for you to do something in the beginning at the end of the question. They rather put the question and command you to do stuff in chronological order...

13. algebra2sucks Group Title

Ooooh ok so its just -5, and -4??

14. algebra2sucks Group Title

Is that right @Azteck

15. Azteck Group Title

Why -5?

16. Azteck Group Title

Put -5 into that fraction. What do you get? Do you undefined? If you don't get undefined, then -5 ain't restricting noone.

17. algebra2sucks Group Title

Well these are the answers I have A. (x+2)(x+5)/x+4; x = -5, -4 B. (x+2)(x+4)/(x+4)^2(x+5); x = 1, -5 C. (x+2)(x+4)/(x+4)^2(x+5); x = 1, -5,-4 D. (x+2)(x+5)/x+4; x = 1, -4, -5

18. Azteck Group Title

Then you have to find the restrictions in the quotient. So you were correct before. D is the answer. These questions are dodgy, if they didn't give you multiple choice. Next time write the WHOLE QUESTION down before you post...