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haltiamali

(2a^3b^2) (b^3)^2 Simplify. (The ^'s mean to the power of..)

  • one year ago
  • one year ago

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  1. ajprincess
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    \(\large (x^y)^z)=x^{y*z}\) using this can u simplify \(\large (b^3)^2\)?

    • one year ago
  2. haltiamali
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    So it would be \[b^6..?\]

    • one year ago
  3. ajprincess
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    ya very good:)

    • one year ago
  4. ajprincess
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    \(\large x^y*x^z=x^{y+z}\) Usin this can u simplify \(\large b^2*b^6\)?

    • one year ago
  5. haltiamali
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    Is the answer \[2a^5b^12\]

    • one year ago
  6. haltiamali
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    that last number is supposed to be a 12

    • one year ago
  7. ajprincess
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    nope. \(\large x^y*x^z=x^{y+z}\) using this hint can u simplify \(\large b^2*b^6\)?

    • one year ago
  8. haltiamali
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    \[b^8?\]

    • one year ago
  9. ajprincess
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    ya very good:)

    • one year ago
  10. haltiamali
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    \[2a^3b^8\] is the answer?

    • one year ago
  11. ajprincess
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    yup:)

    • one year ago
  12. haltiamali
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    thx. :) can you help me with the other 3?

    • one year ago
  13. ajprincess
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    ya sure:)

    • one year ago
  14. haltiamali
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    \[(-4xy)^3 (-2x^2)^3\]

    • one year ago
  15. ajprincess
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    \(\Large (-2x^2)^2=(-2)^2*(x^2)^2\) What is \(\Large (-2)^2\)?

    • one year ago
  16. haltiamali
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    4

    • one year ago
  17. ajprincess
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    ya good:) What do u get when u simplify \(\Large (x^2)^2\)?

    • one year ago
  18. haltiamali
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    4x?

    • one year ago
  19. ajprincess
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    nope \(\Large (a^b)^c=a^{b*c}\) using this simplify \(\Large (x^2)^2\)

    • one year ago
  20. haltiamali
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    ohh. \[x^4\] right?

    • one year ago
  21. ajprincess
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    ya:) \(\Large(-4xy)^3=(-4)^3*(x^1)^3*(y^1)^3\) Nw can u simplify (-4)^3*(x^1)^3*(y^1)^3\)

    • one year ago
  22. haltiamali
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    -64 x^4 y^4?

    • one year ago
  23. haltiamali
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    oh wait

    • one year ago
  24. haltiamali
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    hahaha I get it :D

    • one year ago
  25. haltiamali
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    \[(-14xy^4) (-1/2xy^3)\]

    • one year ago
  26. haltiamali
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    that's negative half

    • one year ago
  27. haltiamali
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    Would it be \[-14 1/2 x+y^7?\]

    • one year ago
  28. ajprincess
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    wait a sec. oops sorry it is \(\Large (-2x^2)^3\) right? So \(\Large (-2x^2)^3=(-2)^3*(x^2)^3\) We r nt yet done with our previous problem. so it will be better if we finish that and come to this one. What is \((-2)^3)? What do u get when u simplify \((x^2)^3\)?

    • one year ago
  29. haltiamali
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    \[(-2x^6) \] right?

    • one year ago
  30. ajprincess
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    \(\Large (x^2)^3=x^6\) that's right:) but what is \(\Large (-2)^3=?

    • one year ago
  31. haltiamali
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    oh -8

    • one year ago
  32. ajprincess
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    ya:) so \(\Large (-2x^2)^3=-8x^6\) Nw \(\Large(-4xy)^3=(-4)^3*(x^1)^3*(y^1)^3\) What is \(\Large (-4)^3=\)? What do u get when u simplify \(\Large (x^1)^3\) and \(\Large (y^1)^3\)?

    • one year ago
  33. haltiamali
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    -64 x^4 and y^4

    • one year ago
  34. ajprincess
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    \(\Large(a^b)^c=a^{b*c}\) usin this general rule only u have to simplify \((x^1)^3\) and \((y^1)^3\)

    • one year ago
  35. haltiamali
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    oh. x^3 and y^3

    • one year ago
  36. ajprincess
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    ya good:)

    • one year ago
  37. ajprincess
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    \(\Large(-4xy)^3=-64x^3y^3\) \(\Large(-2x2)^3=-8x^6\) \(\Large(-64x^3y^3)*(-8x^6)=(-64*8)*(x^3*x^6)*y^3\) To simplify \(\Large(x^3*x^6)\) u have to use the general rule \(\Large(a^b)*(a^c)=a^{b+c}\)

    • one year ago
  38. ajprincess
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    Can u figure out the final answer @haltiamali

    • one year ago
  39. haltiamali
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    yes :) tysm

    • one year ago
  40. ajprincess
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    k nw moving on to ur next problem \[(-14xy^4)(\frac{ -1 }{ 2 }xy^3)=(-14*-\frac{ 1 }{ 2 })(x^1*x^1)*(y^4*y^3)\] See if u can simplify nw. If u find any difficulties while solving pls do ask:)

    • one year ago
  41. haltiamali
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    Thanks ! :)

    • one year ago
  42. ajprincess
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    Welcome:)

    • one year ago
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