haltiamali
(2a^3b^2) (b^3)^2
Simplify. (The ^'s mean to the power of..)
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ajprincess
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\(\large (x^y)^z)=x^{y*z}\)
using this can u simplify \(\large (b^3)^2\)?
haltiamali
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So it would be \[b^6..?\]
ajprincess
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ya very good:)
ajprincess
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\(\large x^y*x^z=x^{y+z}\)
Usin this can u simplify
\(\large b^2*b^6\)?
haltiamali
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Is the answer \[2a^5b^12\]
haltiamali
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that last number is supposed to be a 12
ajprincess
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nope.
\(\large x^y*x^z=x^{y+z}\)
using this hint can u simplify
\(\large b^2*b^6\)?
haltiamali
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\[b^8?\]
ajprincess
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ya very good:)
haltiamali
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\[2a^3b^8\] is the answer?
ajprincess
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yup:)
haltiamali
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thx. :) can you help me with the other 3?
ajprincess
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ya sure:)
haltiamali
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\[(-4xy)^3 (-2x^2)^3\]
ajprincess
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\(\Large (-2x^2)^2=(-2)^2*(x^2)^2\)
What is \(\Large (-2)^2\)?
haltiamali
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4
ajprincess
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ya good:)
What do u get when u simplify \(\Large (x^2)^2\)?
haltiamali
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4x?
ajprincess
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nope
\(\Large (a^b)^c=a^{b*c}\)
using this simplify
\(\Large (x^2)^2\)
haltiamali
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ohh. \[x^4\] right?
ajprincess
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ya:)
\(\Large(-4xy)^3=(-4)^3*(x^1)^3*(y^1)^3\)
Nw can u simplify
(-4)^3*(x^1)^3*(y^1)^3\)
haltiamali
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-64 x^4 y^4?
haltiamali
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oh wait
haltiamali
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hahaha I get it :D
haltiamali
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\[(-14xy^4) (-1/2xy^3)\]
haltiamali
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that's negative half
haltiamali
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Would it be \[-14 1/2 x+y^7?\]
ajprincess
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wait a sec.
oops sorry
it is \(\Large (-2x^2)^3\) right?
So
\(\Large (-2x^2)^3=(-2)^3*(x^2)^3\)
We r nt yet done with our previous problem. so it will be better if we finish that and come to this one.
What is \((-2)^3)?
What do u get when u simplify \((x^2)^3\)?
haltiamali
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\[(-2x^6) \] right?
ajprincess
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\(\Large (x^2)^3=x^6\)
that's right:) but what is \(\Large (-2)^3=?
haltiamali
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oh -8
ajprincess
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ya:) so \(\Large (-2x^2)^3=-8x^6\)
Nw
\(\Large(-4xy)^3=(-4)^3*(x^1)^3*(y^1)^3\)
What is \(\Large (-4)^3=\)?
What do u get when u simplify \(\Large (x^1)^3\) and \(\Large (y^1)^3\)?
haltiamali
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-64
x^4 and y^4
ajprincess
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\(\Large(a^b)^c=a^{b*c}\)
usin this general rule only u have to simplify \((x^1)^3\) and \((y^1)^3\)
haltiamali
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oh.
x^3 and y^3
ajprincess
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ya good:)
ajprincess
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\(\Large(-4xy)^3=-64x^3y^3\)
\(\Large(-2x2)^3=-8x^6\)
\(\Large(-64x^3y^3)*(-8x^6)=(-64*8)*(x^3*x^6)*y^3\)
To simplify \(\Large(x^3*x^6)\) u have to use the general rule
\(\Large(a^b)*(a^c)=a^{b+c}\)
ajprincess
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Can u figure out the final answer @haltiamali
haltiamali
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yes :) tysm
ajprincess
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k nw moving on to ur next problem
\[(-14xy^4)(\frac{ -1 }{ 2 }xy^3)=(-14*-\frac{ 1 }{ 2 })(x^1*x^1)*(y^4*y^3)\]
See if u can simplify nw. If u find any difficulties while solving pls do ask:)
haltiamali
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Thanks ! :)
ajprincess
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Welcome:)