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2g of water at a temperature T1=80 C is mixed with 2g of ice at a temperature of T2=0 C.
I assumed heat lost by the water is heat gained by the ice. Q(water)= Q(ice)
Where Q(water)= mc∆T
and Q(ice) = mL + mc∆T
I got final temperature is 0 C or 273 K. Anyone back me up?
 one year ago
 one year ago
2g of water at a temperature T1=80 C is mixed with 2g of ice at a temperature of T2=0 C. I assumed heat lost by the water is heat gained by the ice. Q(water)= Q(ice) Where Q(water)= mc∆T and Q(ice) = mL + mc∆T I got final temperature is 0 C or 273 K. Anyone back me up?
 one year ago
 one year ago

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