AdhaZeera
Is my work correct?



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AdhaZeera
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\[4^{2x}*4^{x}= 64 \]

AdhaZeera
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x = 3

AdhaZeera
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\[2^{x}*\frac{ 1 }{ 32 }=32\]

AdhaZeera
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x=10

AdhaZeera
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\[64 * 16^{3x}=16^{3x2}\]
This on I'm confused on. x=0?

Azteck
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Correct for both.

Azteck
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Last one I will show you.

Azteck
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\[4^3\times (4^2)^{3x}=(4^2)^{3x2}\]
\[4^3\times 4^{(2)(3x)}=4^{2(3x2)}\]

Azteck
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\[4^{36x}=4^{6x4}\]
\[36x=6x4\]
\[12x=7\]

AdhaZeera
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Oh, I see what I did! I cancelled out 6x with the positive 6x. lol, thank you very much!