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AdhaZeera

  • 3 years ago

Is my work correct?

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  1. AdhaZeera
    • 3 years ago
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    \[4^{-2x}*4^{x}= 64 \]

  2. AdhaZeera
    • 3 years ago
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    x = -3

  3. AdhaZeera
    • 3 years ago
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    \[2^{x}*\frac{ 1 }{ 32 }=32\]

  4. AdhaZeera
    • 3 years ago
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    x=10

  5. AdhaZeera
    • 3 years ago
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    \[64 * 16^{-3x}=16^{3x-2}\] This on I'm confused on. x=0?

  6. Azteck
    • 3 years ago
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    Correct for both.

  7. Azteck
    • 3 years ago
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    Last one I will show you.

  8. Azteck
    • 3 years ago
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    \[4^3\times (4^2)^{-3x}=(4^2)^{3x-2}\] \[4^3\times 4^{(2)(-3x)}=4^{2(3x-2)}\]

  9. Azteck
    • 3 years ago
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    \[4^{3-6x}=4^{6x-4}\] \[3-6x=6x-4\] \[12x=7\]

  10. AdhaZeera
    • 3 years ago
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    Oh, I see what I did! I cancelled out -6x with the positive 6x. lol, thank you very much!

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