## ineedyouubiebs 2 years ago Where do the graphs of the following equations intersect: x-y=3 x=-2y-6 please someone who is actually willing to help me i struggle on this

1. omoshiroi

ok. first you need to have one of the equations in terms of x or y. Lets take x-y=3. solve for x ineedyouubiebs

2. ineedyouubiebs

3. omoshiroi

no, it does not matter. but x-y=3 is easier to work with.

4. Eminy

Solve for y, x-y=3 -x -y=-x+3 times -1 y=x-3 x=-2y-6 -6 x-6=-2y divde buy -2 -1/2x+3=y or y=-1/2x+3

5. ineedyouubiebs

would it be (-2y-6)-y=3 ?? please correct me if im wrong

6. dpaInc

@ineedyouubiebs , that would be correct... ^^^

7. ineedyouubiebs

omgggg yesss!!

8. omoshiroi

yes that is correct

9. ineedyouubiebs

@dpaInc and how would i add like terms to that...i mean would i have to distribute?

10. dpaInc

technically you are distributing a "1" in 1(-2y-6)-y=3 but since it is only a positive 1, just get rid of the parenthesis to get: -2y - 6 - y = 3 now combine like terms and solve....

11. ineedyouubiebs

y=-3

12. dpaInc

correct... now solve for x...

13. ineedyouubiebs

and how would i do that?

14. dpaInc

you have x = -2y - 6 from the beginning....

15. dpaInc

just plug in the value that you found for y: x = -2(-3) - 6

16. ineedyouubiebs

x=6-6

17. dpaInc

simplify that....

18. ineedyouubiebs

x=0

19. dpaInc

you're basically done... and whenever you need to see if your answer is correct or not, plug in the values of both x and y into BOTH equations. if they both turn out to be true statements, your answer is correct.

20. ineedyouubiebs

okay thank you soo much=D can you help me in another problem?

21. dpaInc

sure.... close this question and post a new one.... :)