ineedyouubiebs
Where do the graphs of the following equations intersect: x-y=3
x=-2y-6 please someone who is actually willing to help me i struggle on this
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omoshiroi
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ok. first you need to have one of the equations in terms of x or y.
Lets take x-y=3. solve for x ineedyouubiebs
ineedyouubiebs
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so it doesnt matter which one i start with?
omoshiroi
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no, it does not matter. but x-y=3 is easier to work with.
Eminy
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Solve for y,
x-y=3
-x
-y=-x+3
times -1
y=x-3
x=-2y-6
-6
x-6=-2y
divde buy -2
-1/2x+3=y
or
y=-1/2x+3
ineedyouubiebs
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would it be (-2y-6)-y=3 ?? please correct me if im wrong
dpaInc
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@ineedyouubiebs , that would be correct... ^^^
ineedyouubiebs
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omgggg yesss!!
omoshiroi
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yes that is correct
ineedyouubiebs
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@dpaInc and how would i add like terms to that...i mean would i have to distribute?
dpaInc
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technically you are distributing a "1" in 1(-2y-6)-y=3
but since it is only a positive 1, just get rid of the parenthesis to get: -2y - 6 - y = 3
now combine like terms and solve....
ineedyouubiebs
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y=-3
dpaInc
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correct...
now solve for x...
ineedyouubiebs
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and how would i do that?
dpaInc
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you have x = -2y - 6 from the beginning....
dpaInc
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just plug in the value that you found for y: x = -2(-3) - 6
ineedyouubiebs
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x=6-6
dpaInc
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simplify that....
ineedyouubiebs
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x=0
dpaInc
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you're basically done... and whenever you need to see if your answer is correct or not, plug in the values of both x and y into BOTH equations. if they both turn out to be true statements, your answer is correct.
ineedyouubiebs
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okay thank you soo much=D can you help me in another problem?
dpaInc
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sure.... close this question and post a new one.... :)