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ikshjbdckoj Group Title

Someone I need help..! If the force of 12 N is applied to an object with a mass of 2 kg, the object will accelerate at 0.17 m/s². 24 m/s². 6 m/s². 12 m/s².

  • one year ago
  • one year ago

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  1. ikshjbdckoj Group Title
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    I think there's a formula for this just not sure.

    • one year ago
  2. mathstudent55 Group Title
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    F = ma

    • one year ago
  3. mathstudent55 Group Title
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    F = force, m = mass, a = acceleration

    • one year ago
  4. ikshjbdckoj Group Title
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    okay so it would look like 12= 12 something? I dont know what that is yet.

    • one year ago
  5. mathstudent55 Group Title
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    F = ma, you have the force and the mass and are looking for the acceleration, so solve F = ma for a. Then plug in the values you have and get a value for a.

    • one year ago
  6. ikshjbdckoj Group Title
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    Well I kindof understand that but not all the way. I don't understand how to plug in the numbers to the formula. I'm not good at formulas.

    • one year ago
  7. mathstudent55 Group Title
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    a = F/m

    • one year ago
  8. mathstudent55 Group Title
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    a = F/m = 12 N/2 kg = 6 (kg-m/s^2)/kg = 6 m/s^2

    • one year ago
  9. ikshjbdckoj Group Title
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    Oh lord, thats a lot of working out...

    • one year ago
  10. ikshjbdckoj Group Title
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    OHHH so is the answer 6???

    • one year ago
  11. raden_zaikaria Group Title
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    |dw:1360082146175:dw|

    • one year ago
  12. raden_zaikaria Group Title
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    |dw:1360082184212:dw|

    • one year ago
  13. ikshjbdckoj Group Title
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    oh so im right?:) Cause I'm really confused actually.

    • one year ago
  14. ikshjbdckoj Group Title
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    I didn't work it out like that. I just divided 12/2 got 6 and saw 6 and thought that was the answer.

    • one year ago
  15. mathstudent55 Group Title
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    The answer is 6 m/s^2. An acceleration is given in units of acceleration. In this case the units were meters per second square. Notice that all the choices for answers are in m/s^2.

    • one year ago
  16. ikshjbdckoj Group Title
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    ohhhhhhhhhh okay... I got it now. Thanks :)

    • one year ago
  17. mathstudent55 Group Title
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    You're welcome.

    • one year ago
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