## iloveyahhhh Group Title Find the limit as x approaches 0 for (x^2-3sinx)/x one year ago one year ago

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1. mathsmind Group Title

the limit =-3

2. mathsmind Group Title

$\lim_{x \rightarrow 0}\frac{ 2x -3cosx}{ 1}$

3. ZeHanz Group Title

@mathsmind has done it with l'Hôpital's Rule. That's ok. This one could also be done in a more basic way. Split up: $\lim_{x \rightarrow 0}\frac{ x^2 }{ x }-3\lim_{x \rightarrow 0}\frac{ \sin x }{ x }$ The left one is just$\lim_{x \rightarrow 0}\frac{ x \cdot x }{ x }=\lim_{x \rightarrow 0}x=0$The right one is 3 times the well-known standard limit (with an outcome of 1) So the result would be 0-3*1=-3.

4. mathsmind Group Title

these problem can be worked out just by looking at them

5. mathsmind Group Title

but it seems even when you tell the rules they repeat same question over and over again

6. ZeHanz Group Title

Just keep explaining will help. Sooner or later, the understanding will arrive...