A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Find the limit as x approaches 0 for (x^23sinx)/x
anonymous
 3 years ago
Find the limit as x approaches 0 for (x^23sinx)/x

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}\frac{ 2x 3cosx}{ 1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind has done it with l'Hôpital's Rule. That's ok. This one could also be done in a more basic way. Split up: \[\lim_{x \rightarrow 0}\frac{ x^2 }{ x }3\lim_{x \rightarrow 0}\frac{ \sin x }{ x }\] The left one is just\[\lim_{x \rightarrow 0}\frac{ x \cdot x }{ x }=\lim_{x \rightarrow 0}x=0\]The right one is 3 times the wellknown standard limit (with an outcome of 1) So the result would be 03*1=3.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these problem can be worked out just by looking at them

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but it seems even when you tell the rules they repeat same question over and over again

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just keep explaining will help. Sooner or later, the understanding will arrive...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.