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JonaskBest ResponseYou've already chosen the best response.0
f(x+h) means where you see the x you add h DO NOT FOCUS ON OTHER NUMBERS
 one year ago

ZeldaBest ResponseYou've already chosen the best response.0
10x Should be the final answer.
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
@Zelda theres no limit here
 one year ago

april1reneeBest ResponseYou've already chosen the best response.0
5(x+h)^2 f(5x^2) ??
 one year ago

april1reneeBest ResponseYou've already chosen the best response.0
5(x^2+2xh+h^2)= 5x^2+10xh+5h^2
 one year ago

ZeldaBest ResponseYou've already chosen the best response.0
Hey april, is there the word lim as h> 0 before f(x)?
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
5x^2+10xh+5h^2(5x^2+10x+5h)=
 one year ago

april1reneeBest ResponseYou've already chosen the best response.0
the answer i have is 10x+5h
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
yes but is there any thing like this \[\lim_{h \rightarrow 0}\] on the question
 one year ago

april1reneeBest ResponseYou've already chosen the best response.0
professor answer is 5(2x+h) i dont undestand why i would divide by 5
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
It would be (very much) more clear if everyone wouldn't just write peaces of the problem, but the whole thing:\[\frac{ f(x+h)f(x) }{ h }=\frac{ 5(x+h)^25x^2 }{ h }=\frac{ 5(x^2+2xh+h^2)5x^2 }{ h }\]See? Just keep on writing the complete fraction, simpifying it along the way, until you're done:\[\frac{ 5x^2+10xh+5h^25x^2 }{ h }=\frac{ 10xh+5h^2 }{ h }=\frac{ 5h(2x+h) }{ h }=5(2x+h)\]So finally we've lost the fraction! Sooner or later the question of what will happen if h goes to 0 will be asked. Here you see immediately that leads to 10x.
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
Of course, you could write the answer also as 10x + 5h
 one year ago
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