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anonymous
 3 years ago
f(x)=5x^2 f(x+h)f(x)/h
anonymous
 3 years ago
f(x)=5x^2 f(x+h)f(x)/h

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0f(x+h) means where you see the x you add h DO NOT FOCUS ON OTHER NUMBERS

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010x Should be the final answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Zelda theres no limit here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05(x^2+2xh+h^2)= 5x^2+10xh+5h^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hey april, is there the word lim as h> 0 before f(x)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05x^2+10xh+5h^2(5x^2+10x+5h)=

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answer i have is 10x+5h

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes but is there any thing like this \[\lim_{h \rightarrow 0}\] on the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0professor answer is 5(2x+h) i dont undestand why i would divide by 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It would be (very much) more clear if everyone wouldn't just write peaces of the problem, but the whole thing:\[\frac{ f(x+h)f(x) }{ h }=\frac{ 5(x+h)^25x^2 }{ h }=\frac{ 5(x^2+2xh+h^2)5x^2 }{ h }\]See? Just keep on writing the complete fraction, simpifying it along the way, until you're done:\[\frac{ 5x^2+10xh+5h^25x^2 }{ h }=\frac{ 10xh+5h^2 }{ h }=\frac{ 5h(2x+h) }{ h }=5(2x+h)\]So finally we've lost the fraction! Sooner or later the question of what will happen if h goes to 0 will be asked. Here you see immediately that leads to 10x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Of course, you could write the answer also as 10x + 5h
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