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missashleyn
Group Title
Someone please help?
Let f(x) = x2 – 16. Find f–1(x).
 one year ago
 one year ago
missashleyn Group Title
Someone please help? Let f(x) = x2 – 16. Find f–1(x).
 one year ago
 one year ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if we solve the problem: y = x^2  16; for x, what does it look like?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
and technically, there is no inverse function stated in the choices :/
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
I have no idea :(
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
we need to remember how to manipulate equation around to solve for a particular variable: y = x^2  16 this can be algebrated about to solve for x
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
What would I do first?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
would you agree that we can subtract 16 from each side to start to get x all alone?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
err, add 16 to each side that is
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Yes so it would be y = x^2/16? So C?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
y = x^2  16 +16 +16  y+16 = x^2 its not C, I havent gotten to the end results yet .....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
do you know how we can get the "^2" off the x?
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Multiply it?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good attempt, but lets try to take the square root, or sqrt it sqrt(y+16) = sqrt(x^2) sqrt(y+16) = x this is the general construct of our inverse function we are looking for, but they like to then swap xs and ys
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Ohhhhh so it's B then?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
B seems the most reasonable answer to me :)
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Okay thank you! I have one more like this, could you help me with it too?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i can take a look at it sure
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Let f(x) = 5x + 12. Find f–1(x).
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
lets try the same process, but this one is simpler since we aint got to sqrt nothing y = 5x + 12 how do we solve for x so that x is all alone on one side of the equation?
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
 12 from each side y = 5x + 12  12  12 y  12 = 5x
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
so far so good, now to uncover the x, we should divide off that pesky looking 5 right?
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Yes so.. y  12 = 5x  5 y  12/5 = x
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
I think I'm confusing myself
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
you did fine, lets just make sure its looks "proper" :) \[\frac{y12}{5}=x\]
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Okay the closest choice I have to that is dw:1360095933270:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
that will work fine ;)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good luck
 one year ago

missashleyn Group TitleBest ResponseYou've already chosen the best response.0
Okay awesome, thank you!! :)
 one year ago
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