Someone please help?
Let f(x) = x2 – 16. Find f–1(x).

- anonymous

Someone please help?
Let f(x) = x2 – 16. Find f–1(x).

- jamiebookeater

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- anonymous

##### 1 Attachment

- amistre64

if we solve the problem:
y = x^2 - 16; for x, what does it look like?

- amistre64

and technically, there is no inverse function stated in the choices :/

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## More answers

- anonymous

I have no idea :(

- amistre64

we need to remember how to manipulate equation around to solve for a particular variable:
y = x^2 - 16
this can be algebrated about to solve for x

- anonymous

What would I do first?

- amistre64

would you agree that we can subtract 16 from each side to start to get x all alone?

- amistre64

err, add 16 to each side that is

- anonymous

Yes so it would be y = x^2/16? So C?

- amistre64

y = x^2 - 16
+16 +16
----------------
y+16 = x^2
its not C, I havent gotten to the end results yet .....

- amistre64

do you know how we can get the "^2" off the x?

- anonymous

Multiply it?

- amistre64

good attempt, but lets try to take the square root, or sqrt it
sqrt(y+16) = sqrt(x^2)
sqrt(y+16) = x
this is the general construct of our inverse function we are looking for, but they like to then swap xs and ys

- anonymous

Ohhhhh so it's B then?

- amistre64

B seems the most reasonable answer to me :)

- anonymous

Okay thank you! I have one more like this, could you help me with it too?

- amistre64

i can take a look at it sure

- anonymous

Let f(x) = 5x + 12. Find f–1(x).

- amistre64

lets try the same process, but this one is simpler since we aint got to sqrt nothing
y = 5x + 12
how do we solve for x so that x is all alone on one side of the equation?

- anonymous

- 12 from each side
y = 5x + 12
- 12 - 12
y - 12 = 5x

- amistre64

so far so good, now to uncover the x, we should divide off that pesky looking 5 right?

- anonymous

Yes so..
y - 12 = 5x
----------
5
y - 12/5 = x

- anonymous

I think I'm confusing myself

- amistre64

you did fine, lets just make sure its looks "proper" :)
\[\frac{y-12}{5}=x\]

- anonymous

Okay the closest choice I have to that is |dw:1360095933270:dw|

- amistre64

that will work fine ;)

- amistre64

good luck

- anonymous

Okay awesome, thank you!! :)

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