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 2 years ago
PLEASE HELKP ME IM BEHIND PLEASE EXPLAIN STEPS AND I WILL GIVE YOU A MEDAL. Factor the trinomial: 4x^2  8x  5
(2x + 1)(2x  5)
(4x + 1)(x  5)
(4x  5)(x + 1)
prime
 2 years ago
PLEASE HELKP ME IM BEHIND PLEASE EXPLAIN STEPS AND I WILL GIVE YOU A MEDAL. Factor the trinomial: 4x^2  8x  5 (2x + 1)(2x  5) (4x + 1)(x  5) (4x  5)(x + 1) prime

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precal
 2 years ago
Best ResponseYou've already chosen the best response.0I am going to teach you a method called slide and divide take the 1st number and slide it to the back by multiplying it to the last number

precal
 2 years ago
Best ResponseYou've already chosen the best response.0we know x times x is x to the second power we are using 10 and 2 because 10 times 2 is 20 but we need to subtract them to get 8 the minus sign in front of 20 tells us to subtract those two numbers

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095517633:dw what happened there?

precal
 2 years ago
Best ResponseYou've already chosen the best response.0+210 gives us 8 we need 8x

precal
 2 years ago
Best ResponseYou've already chosen the best response.0last step is to divid the number back in

precal
 2 years ago
Best ResponseYou've already chosen the best response.0because 1/2 is a decimal we will now take the 2 and move it in front of x and drop the 1

precal
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095620919:dwwe are done

precal
 2 years ago
Best ResponseYou've already chosen the best response.0you can read through each step until you learn the pattern

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095653585:dw you lost me here

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0i dont understand what you did

precal
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095676993:dwyou have to list all of the products of 20

precal
 2 years ago
Best ResponseYou've already chosen the best response.0the sign in front of 20 tells you to subtract them, you are looking for the middle term

precal
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095763812:dwuse 2 and 10

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0but that would be positive 20

precal
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360095780117:dwthese are your sign choices

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0ok look i found 2, and 10 to be the correct factors all i wanted to know was how to inser that into the equation and solve

precal
 2 years ago
Best ResponseYou've already chosen the best response.02 must be positive and 10 must be negative

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0ok im sorry i made a huge mistaje when writting this i didnt use the ^

precal
 2 years ago
Best ResponseYou've already chosen the best response.0does not change my answer since I did use the correct notation

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0can you please not use the drawing i cant read it or understand it..im sorry im just so confused at how you got your answer and i understand if you want to just give up on me..

precal
 2 years ago
Best ResponseYou've already chosen the best response.0sorry need to go, repost your problem someone will come help you

rosedewittbukater
 2 years ago
Best ResponseYou've already chosen the best response.14x^2  8x  5 Ok so I'll try to explain this the way I understand it. Usually to factor you have to find 2 numbers that multiply to equal the last number, and add up to equal the number part of the middle. I'll just use \[ax ^{2}+bx+c\] as an example equation. So you have to find 2 numbers that multiply to get c, and add up to get b. Then you would usually take those 2 numbers and use it to factor and get (x+?)(x+?). But since there is a number for a that is not 1 in your equation, it's a little different. First, multiply the first and last numbers 4 and 5 (a and c in the example equation). You get 20. So try to find 2 number that are factors of 20 and add up to equal 8. Just start to list the factors off on paper or in your head. Remember to include the negatives. 1, 20 1, 20 2, 10 2, 10 These add up to equal 8 Then put 2 and 10 to separate the middle part of the equation. \[4x ^{2}+2x10x5\]Then group the equation into 2 separate parts. \[(4x ^{2}+2x)+(10x5)\]Then you take out any common factors from the parentheses.\[2x(2x+1)5(2x+1)\]And then group together the parts you took out, which are the 2x and 5.\[(2x5)(2x+1)\]It becomes this because 2x+1 are the same. There's your answer. Hope this helps!

precal
 2 years ago
Best ResponseYou've already chosen the best response.0yes rose is showing the method known as factor by grouping. Both methods are correct
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