Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the limit of this look at the attached file

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

1 Attachment
1 Attachment
@jim_thompson5910 they said u could help

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I think the answer does not Exist
using the limit laws, we can say \[\Large \lim_{x\to 2}x^3 f(x) = (\lim_{x\to 2}x^3) * (\lim_{x\to 2}f(x))\] \[\Large \lim_{x\to 2}x^3 f(x) = 2^3 * f(2)\] \[\Large \lim_{x\to 2}x^3 f(x) = 8 * f(2)\] \[\Large \lim_{x\to 2}x^3 f(x) = ???\]
to find f(2) you would either use a function or the graph since you don't have the function, you'll have to use the graph
but the graph has a hole and a solution thats where im confused
at x->2
ok as x gets closer and closer to 2, the graph is approaching the point (2,2) sure there is a hole here, but if you start on either side of x = 2 and approach it, you'll reach this hole so that's why \[\Large \lim_{x\to 2} f(x) = 2\]
\[\Large \lim_{x\to 2}x^3 f(x) = (\lim_{x\to 2}x^3) * (\lim_{x\to 2}f(x))\] \[\Large \lim_{x\to 2}x^3 f(x) = 2^3 * 2\] \[\Large \lim_{x\to 2}x^3 f(x) = 8 * 2\] \[\Large \lim_{x\to 2}x^3 f(x) = 16\]
oh... I see.. Thanks a lot! I have another question.. Could I ask you?
sure go for it
If f and g are continuous functions with f(1) = 5 and the following limit, find g(1).
1 Attachment
im getting 8 as a result not sure
this is a completely different problem right (with different functions f and g)?
oh wait nvm
yes
that's correct, g(1) = 8
you separate the limit up plug in x = 1 then replace f(1) with 5 and g(1) with y afterwards you solve for y to get y = 8
yay! Thank You so much for your help!
you're welcome

Not the answer you are looking for?

Search for more explanations.

Ask your own question