anonymous
  • anonymous
Help with #6 on the worksheet....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
this is what i have: |dw:1360104752412:dw|
anonymous
  • anonymous
b) Expected Value (Height) = ? c) Pr(X>160) d) e) Pr(165185) Help????

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anonymous
  • anonymous
@robtobey @phi
anonymous
  • anonymous
ok b) is 1/(b-a) so 1/(210-150)
anonymous
  • anonymous
hi @Jemurray3 ! :D
anonymous
  • anonymous
**** c) Pr(X<160)
anonymous
  • anonymous
What you said above, 1/(b-a), is the probability density function: P(x) = 1/(b-a) for all x between a and b, and zero elsewhere. Because it's constant, you can multiply it by the length of any interval to find the probability that someone's height falls in said interval. So, (c) is (160-150) / (210-150) = 10/60 = 1/6.
anonymous
  • anonymous
o ok i see... please continue.... my notes have what you just said but are not very clear....
anonymous
  • anonymous
for D would it be 2 times the numerator??
anonymous
  • anonymous
The expectation value is fairly clearly the average height. The rest are just multiplying your probability density function by intervals of different lengths.
anonymous
  • anonymous
No, it is not. If A and B are uncorrelated random events, then P(A and B) = P(A) * P(B)
anonymous
  • anonymous
so 1/6 times 1/6 ??
anonymous
  • anonymous
Yes
anonymous
  • anonymous
sweeeeet
anonymous
  • anonymous
for part E would i do: (185-165)/(210-150) ??
anonymous
  • anonymous
yes
anonymous
  • anonymous
and F would be (210-200)/(210-150) ?? lol
anonymous
  • anonymous
@Jemurray3 , you still alive? haha
anonymous
  • anonymous
You seem to understand it well enough without me at this point
anonymous
  • anonymous
ok. im just making sure.

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