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Help with #6 on the worksheet....

Mathematics
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1 Attachment
this is what i have: |dw:1360104752412:dw|
b) Expected Value (Height) = ? c) Pr(X>160) d) e) Pr(165185) Help????

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ok b) is 1/(b-a) so 1/(210-150)
hi @Jemurray3 ! :D
**** c) Pr(X<160)
What you said above, 1/(b-a), is the probability density function: P(x) = 1/(b-a) for all x between a and b, and zero elsewhere. Because it's constant, you can multiply it by the length of any interval to find the probability that someone's height falls in said interval. So, (c) is (160-150) / (210-150) = 10/60 = 1/6.
o ok i see... please continue.... my notes have what you just said but are not very clear....
for D would it be 2 times the numerator??
The expectation value is fairly clearly the average height. The rest are just multiplying your probability density function by intervals of different lengths.
No, it is not. If A and B are uncorrelated random events, then P(A and B) = P(A) * P(B)
so 1/6 times 1/6 ??
Yes
sweeeeet
for part E would i do: (185-165)/(210-150) ??
yes
and F would be (210-200)/(210-150) ?? lol
@Jemurray3 , you still alive? haha
You seem to understand it well enough without me at this point
ok. im just making sure.

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