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mariomintchev

Help with #6 on the worksheet....

  • one year ago
  • one year ago

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  1. mariomintchev
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    • one year ago
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  2. mariomintchev
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    this is what i have: |dw:1360104752412:dw|

    • one year ago
  3. mariomintchev
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    b) Expected Value (Height) = ? c) Pr(X>160) d) e) Pr(165<x<185) f) Pr(X>185) Help????

    • one year ago
  4. mariomintchev
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    @robtobey @phi

    • one year ago
  5. mariomintchev
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    ok b) is 1/(b-a) so 1/(210-150)

    • one year ago
  6. mariomintchev
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    hi @Jemurray3 ! :D

    • one year ago
  7. mariomintchev
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    **** c) Pr(X<160)

    • one year ago
  8. Jemurray3
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    What you said above, 1/(b-a), is the probability density function: P(x) = 1/(b-a) for all x between a and b, and zero elsewhere. Because it's constant, you can multiply it by the length of any interval to find the probability that someone's height falls in said interval. So, (c) is (160-150) / (210-150) = 10/60 = 1/6.

    • one year ago
  9. mariomintchev
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    o ok i see... please continue.... my notes have what you just said but are not very clear....

    • one year ago
  10. mariomintchev
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    for D would it be 2 times the numerator??

    • one year ago
  11. Jemurray3
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    The expectation value is fairly clearly the average height. The rest are just multiplying your probability density function by intervals of different lengths.

    • one year ago
  12. Jemurray3
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    No, it is not. If A and B are uncorrelated random events, then P(A and B) = P(A) * P(B)

    • one year ago
  13. mariomintchev
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    so 1/6 times 1/6 ??

    • one year ago
  14. Jemurray3
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    Yes

    • one year ago
  15. mariomintchev
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    sweeeeet

    • one year ago
  16. mariomintchev
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    for part E would i do: (185-165)/(210-150) ??

    • one year ago
  17. Jemurray3
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    yes

    • one year ago
  18. mariomintchev
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    and F would be (210-200)/(210-150) ?? lol

    • one year ago
  19. mariomintchev
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    @Jemurray3 , you still alive? haha

    • one year ago
  20. Jemurray3
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    You seem to understand it well enough without me at this point

    • one year ago
  21. mariomintchev
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    ok. im just making sure.

    • one year ago
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