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mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0this is what i have: dw:1360104752412:dw

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0b) Expected Value (Height) = ? c) Pr(X>160) d) e) Pr(165<x<185) f) Pr(X>185) Help????

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0ok b) is 1/(ba) so 1/(210150)

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0hi @Jemurray3 ! :D

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0**** c) Pr(X<160)

Jemurray3
 one year ago
Best ResponseYou've already chosen the best response.1What you said above, 1/(ba), is the probability density function: P(x) = 1/(ba) for all x between a and b, and zero elsewhere. Because it's constant, you can multiply it by the length of any interval to find the probability that someone's height falls in said interval. So, (c) is (160150) / (210150) = 10/60 = 1/6.

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0o ok i see... please continue.... my notes have what you just said but are not very clear....

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0for D would it be 2 times the numerator??

Jemurray3
 one year ago
Best ResponseYou've already chosen the best response.1The expectation value is fairly clearly the average height. The rest are just multiplying your probability density function by intervals of different lengths.

Jemurray3
 one year ago
Best ResponseYou've already chosen the best response.1No, it is not. If A and B are uncorrelated random events, then P(A and B) = P(A) * P(B)

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0so 1/6 times 1/6 ??

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0for part E would i do: (185165)/(210150) ??

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0and F would be (210200)/(210150) ?? lol

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0@Jemurray3 , you still alive? haha

Jemurray3
 one year ago
Best ResponseYou've already chosen the best response.1You seem to understand it well enough without me at this point

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0ok. im just making sure.
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