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happykiddo

  • one year ago

solve the equation by finding the square root x^2-9=0 i got x=4 + or - √4

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  1. JuanitaM
    • one year ago
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    how did you get 4...

  2. JuanitaM
    • one year ago
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    i think you meant to type 3

  3. JuanitaM
    • one year ago
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    |dw:1360110109271:dw| to solve by square root; get the x^2 term by itself and take the square root of each side.

  4. happykiddo
    • one year ago
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    i posted the answer for the wrong question. sorry. would you be willing to help again heres the my actual question 2x^2-64=0 and i got x=4 + or - √4 for this question

  5. suivpasyonw
    • one year ago
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    \[2x ^{2}=64\] \[x ^{2}=32\] \[x=+-\sqrt{32}\]

  6. happykiddo
    • one year ago
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    could i simplify √32 ?

  7. happykiddo
    • one year ago
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    like x=-6+- √27 can be simplified into x=-6+- 3√3

  8. suivpasyonw
    • one year ago
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    of course it would be \[\sqrt{16\times2}\] so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]

  9. suivpasyonw
    • one year ago
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    exact @happykiddo

  10. happykiddo
    • one year ago
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    thanks alot :)

  11. suivpasyonw
    • one year ago
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    u're welcome!

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