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happykiddo Group Title

solve the equation by finding the square root x^2-9=0 i got x=4 + or - √4

  • one year ago
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  1. JuanitaM Group Title
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    how did you get 4...

    • one year ago
  2. JuanitaM Group Title
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    i think you meant to type 3

    • one year ago
  3. JuanitaM Group Title
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    |dw:1360110109271:dw| to solve by square root; get the x^2 term by itself and take the square root of each side.

    • one year ago
  4. happykiddo Group Title
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    i posted the answer for the wrong question. sorry. would you be willing to help again heres the my actual question 2x^2-64=0 and i got x=4 + or - √4 for this question

    • one year ago
  5. suivpasyonw Group Title
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    \[2x ^{2}=64\] \[x ^{2}=32\] \[x=+-\sqrt{32}\]

    • one year ago
  6. happykiddo Group Title
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    could i simplify √32 ?

    • one year ago
  7. happykiddo Group Title
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    like x=-6+- √27 can be simplified into x=-6+- 3√3

    • one year ago
  8. suivpasyonw Group Title
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    of course it would be \[\sqrt{16\times2}\] so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]

    • one year ago
  9. suivpasyonw Group Title
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    exact @happykiddo

    • one year ago
  10. happykiddo Group Title
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    thanks alot :)

    • one year ago
  11. suivpasyonw Group Title
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    u're welcome!

    • one year ago
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