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JuanitaM
 one year ago
Best ResponseYou've already chosen the best response.0i think you meant to type 3

JuanitaM
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360110109271:dw to solve by square root; get the x^2 term by itself and take the square root of each side.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0i posted the answer for the wrong question. sorry. would you be willing to help again heres the my actual question 2x^264=0 and i got x=4 + or  √4 for this question

suivpasyonw
 one year ago
Best ResponseYou've already chosen the best response.1\[2x ^{2}=64\] \[x ^{2}=32\] \[x=+\sqrt{32}\]

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0could i simplify √32 ?

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0like x=6+ √27 can be simplified into x=6+ 3√3

suivpasyonw
 one year ago
Best ResponseYou've already chosen the best response.1of course it would be \[\sqrt{16\times2}\] so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]
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