happykiddo
  • happykiddo
solve the equation by finding the square root x^2-9=0 i got x=4 + or - √4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
how did you get 4...
anonymous
  • anonymous
i think you meant to type 3
anonymous
  • anonymous
|dw:1360110109271:dw| to solve by square root; get the x^2 term by itself and take the square root of each side.

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happykiddo
  • happykiddo
i posted the answer for the wrong question. sorry. would you be willing to help again heres the my actual question 2x^2-64=0 and i got x=4 + or - √4 for this question
anonymous
  • anonymous
\[2x ^{2}=64\] \[x ^{2}=32\] \[x=+-\sqrt{32}\]
happykiddo
  • happykiddo
could i simplify √32 ?
happykiddo
  • happykiddo
like x=-6+- √27 can be simplified into x=-6+- 3√3
anonymous
  • anonymous
of course it would be \[\sqrt{16\times2}\] so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]
anonymous
  • anonymous
exact @happykiddo
happykiddo
  • happykiddo
thanks alot :)
anonymous
  • anonymous
u're welcome!

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