solve the equation by finding the square root x^2-9=0 i got x=4 + or - √4

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solve the equation by finding the square root x^2-9=0 i got x=4 + or - √4

Mathematics
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how did you get 4...
i think you meant to type 3
|dw:1360110109271:dw| to solve by square root; get the x^2 term by itself and take the square root of each side.

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i posted the answer for the wrong question. sorry. would you be willing to help again heres the my actual question 2x^2-64=0 and i got x=4 + or - √4 for this question
\[2x ^{2}=64\] \[x ^{2}=32\] \[x=+-\sqrt{32}\]
could i simplify √32 ?
like x=-6+- √27 can be simplified into x=-6+- 3√3
of course it would be \[\sqrt{16\times2}\] so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]
thanks alot :)
u're welcome!

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