happykiddo
solve the equation by finding the square root
x^2-9=0
i got x=4 + or - √4
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JuanitaM
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how did you get 4...
JuanitaM
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i think you meant to type 3
JuanitaM
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|dw:1360110109271:dw|
to solve by square root; get the x^2 term by itself and take the square root of each side.
happykiddo
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i posted the answer for the wrong question. sorry. would you be willing to help again
heres the my actual question 2x^2-64=0
and i got x=4 + or - √4 for this question
suivpasyonw
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\[2x ^{2}=64\]
\[x ^{2}=32\]
\[x=+-\sqrt{32}\]
happykiddo
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could i simplify √32 ?
happykiddo
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like x=-6+- √27
can be simplified into x=-6+- 3√3
suivpasyonw
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of course it would be \[\sqrt{16\times2}\]
so \[\sqrt{16}\times \sqrt{2}\]=\[4\sqrt{2}\]
suivpasyonw
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exact @happykiddo
happykiddo
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thanks alot :)
suivpasyonw
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u're welcome!