anonymous
  • anonymous
Find the remainder if P(x)=x^3+17 is divided by (x+2).
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
9 ?
anonymous
  • anonymous
The answer is 9, but I dont understand how to get it.
anonymous
  • anonymous
@DarthTony

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Directrix
  • Directrix
@blahblah_who_cares Have you studied synthetic division or the Remainder Theorem?
anonymous
  • anonymous
I have.
Directrix
  • Directrix
Remainder Theorem?
anonymous
  • anonymous
No. Just synthetic. And I might have learned Remainder but I dont recall anything like it. .
dumbcow
  • dumbcow
for (x+2) evaluate f(-2) to get remainder
Directrix
  • Directrix
We can do either here. I will post the Remainder Theorem so that you can tell me if you've ever seen it. Regardless, we will do the problem but will use the method you have studied. Tell me which method after you look at this remainder theorem. Remainder Theorem If a polynomial P( x) is divided by ( x – r), then the remainder of this division is the same as evaluating P( r), and evaluating P( r) for some polynomial P( x) is the same as finding the remainder of P( x) divided by ( x – r).
Directrix
  • Directrix
@blahblah_who_cares
anonymous
  • anonymous
Yah. Ive never learned Remainder Theorem. @Directrix
Directrix
  • Directrix
We'll do synthetic division.
Directrix
  • Directrix
P(x)=x^3+17 is divided by (x+2) P(x) = x^3 + 0x^2 + 0x + 17 divided by (x + 2) |dw:1360114222669:dw|
Directrix
  • Directrix
Does that look familiar?
anonymous
  • anonymous
Ok. So i think my big question here is how to get the -2.
Directrix
  • Directrix
|dw:1360114478786:dw|
Directrix
  • Directrix
Consider this example: Example 1 Find P(–3) if P( x) = 7 x5 – 4 x3 + 2 x –11. There are two methods of finding P(–3). • Method 1: Directly replace –3 for x. • Method 2: Find the remainder of P( x) divided by [ x – (–3)].
anonymous
  • anonymous
No. I mean how did you get -2 from (x+2).
Directrix
  • Directrix
If the divisor is (x +2), for synthetic division, it is written as (x - (-2)) which results in a divisor of (-2).
anonymous
  • anonymous
Oh.. Ok. thanks.

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