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swin2013

FTC and definite integrals?

  • one year ago
  • one year ago

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  1. swin2013
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    integral from (0 to 2) of the function (x^3/3 +2x) dx

    • one year ago
  2. swin2013
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    isn't the anti derivative x^2 + 2?

    • one year ago
  3. swin2013
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    @zepdrix

    • one year ago
  4. zepdrix
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    No the `derivative` is x^2+2. I think you went in the wrong direction :)

    • one year ago
  5. swin2013
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    Ohh ok. so i need to take the derivative -_- lol

    • one year ago
  6. zepdrix
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    You do? :o

    • one year ago
  7. zepdrix
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    Do you know how to apply the `Power Rule` to integrals? :)

    • one year ago
  8. swin2013
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    well it says to evaluate using FTC. yea it's like when you subtract 1 from the exponent

    • one year ago
  9. swin2013
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    something like that hahaha

    • one year ago
  10. swin2013
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    i meant add lol

    • one year ago
  11. swin2013
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    and divide by the exponent

    • one year ago
  12. zepdrix
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    `Power Rule for Derivatives`: ~Multiply by the power. ~Decrease the power by 1. `Power Rule for Integration`: ~Increase the power by 1. ~Divide by the power. Ok good, seems you understand already :)

    • one year ago
  13. swin2013
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    lol yea :) hopefully i don't mess that process up ahahaha

    • one year ago
  14. swin2013
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    x^4/4 +x^2?

    • one year ago
  15. zepdrix
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    One tiny boo boo, you forgot about the 3 under the first term.

    • one year ago
  16. swin2013
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    for the x^3/3 part?

    • one year ago
  17. zepdrix
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    ya

    • one year ago
  18. zepdrix
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    you `gain` a 4 on the bottom, it doesn't change your 3 to a 4 silly!

    • one year ago
  19. swin2013
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    OOPS! x^4/4*3

    • one year ago
  20. swin2013
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    i got 16/3

    • one year ago
  21. zepdrix
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    That's what I'm coming up with also, I think that's correct!

    • one year ago
  22. swin2013
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    thanksssssssssss!

    • one year ago
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