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FTC and definite integrals?

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integral from (0 to 2) of the function (x^3/3 +2x) dx
isn't the anti derivative x^2 + 2?

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Other answers:

No the `derivative` is x^2+2. I think you went in the wrong direction :)
Ohh ok. so i need to take the derivative -_- lol
You do? :o
Do you know how to apply the `Power Rule` to integrals? :)
well it says to evaluate using FTC. yea it's like when you subtract 1 from the exponent
something like that hahaha
i meant add lol
and divide by the exponent
`Power Rule for Derivatives`: ~Multiply by the power. ~Decrease the power by 1. `Power Rule for Integration`: ~Increase the power by 1. ~Divide by the power. Ok good, seems you understand already :)
lol yea :) hopefully i don't mess that process up ahahaha
x^4/4 +x^2?
One tiny boo boo, you forgot about the 3 under the first term.
for the x^3/3 part?
you `gain` a 4 on the bottom, it doesn't change your 3 to a 4 silly!
OOPS! x^4/4*3
i got 16/3
That's what I'm coming up with also, I think that's correct!

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