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ranyai12

  • 3 years ago

Can someone please explain to me how r(t)=(1-t)<1,3,-2>+t<2,-1,3> became r(t)=<1+t,3-4t,-2+5t>

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  1. ranyai12
    • 3 years ago
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    @Azteck can you lease help?!

  2. Azteck
    • 3 years ago
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    what are the these "<" signs doing there?

  3. ranyai12
    • 3 years ago
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    theyre supposed to represent vectors

  4. ranyai12
    • 3 years ago
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    the original question asks find a vectr equation and parametric equations for th line segment that joins the point P(1,3,-2) and Q(2,-1,3)

  5. Azteck
    • 3 years ago
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    I'm not understanding the vector parts. Sorry about this, but unfortunately, I'm not an expert at these sorts of questions. Maybe you should ask someone else. @whpalmer4 are you good at these questions at all?

  6. ranyai12
    • 3 years ago
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    i figured it out thanks sooo much though!

  7. Azteck
    • 3 years ago
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    hahah I didn't even help. Well done ranyai12. Excellent work from you. (Y)

  8. ranyai12
    • 3 years ago
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    lol but you attempted to help which is more than enough! thanks again!

  9. whpalmer4
    • 3 years ago
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    \[r(t) = (1-t)<1,3,-2> + t<2, -1, 3>\]You essentially treat it like distributing and collecting terms: \[r(t) = <1(1-t),3(1-t),-2(1-t)> + <2t,-t,3t> = <1-t+2t, 3-3t-t,-2+2t+3t> =\]\[= <1+t,3-4t,-2+5t>\]

  10. ranyai12
    • 3 years ago
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    yea i realized that thanks so much though! i at first thought it had to del with matrices which is why i got confused

  11. ranyai12
    • 3 years ago
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    deal*

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