A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
A card is drawn at random from a standard 52card deck. Events G and H are:
G= the drawn card is black
H= the drawn card is divisible by 5 (face cards are not valued)
(A)Find P(HIG)
(B)Test H and G for independence
(A)P(HIG)=
 one year ago
A card is drawn at random from a standard 52card deck. Events G and H are: G= the drawn card is black H= the drawn card is divisible by 5 (face cards are not valued) (A)Find P(HIG) (B)Test H and G for independence (A)P(HIG)=

This Question is Closed

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0P(HG) means the probability of H given G. Given that the drawn card is black, the sample space is 26 cards. There are 4 black cards that are either a 5 or a 10. \[P(HG)=\frac{4}{26}=\frac{2}{13}\]

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0@Anita505 Are you there?

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the help! @kropot72

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0however would Test H and G for independence... would it be independent? or dependent?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0If two events A and B are independent, then the probability of A occurring is unaffected by whether of not B has occurred. Therefore if the events are independent P(AB) = P(A) In this case we test whether P(HG) = P(H) There are 8 cards that are 5 or 10 and either black or red. Therefore \[P(H)=\frac{8}{52}=\frac{2}{13}\] Have we confirmed that H and G are independent?

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0Yes this is independent :) thank you once again for your help! much appreciated!

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Correct! You're welcome :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.