Jaweria
  • Jaweria
Can anyone please help me with this question? Find Y prime: Y=cos^-1(2x+5).
Differential Equations
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Jaweria
  • Jaweria
This is the equation: \[Y=\cos^{-1} (2x+5)\]
Jaweria
  • Jaweria
This is a new math to me and the homework is due tomorrow I m stuck with these problems!!
Jaweria
  • Jaweria
I got an answer but it looks weird

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More answers

anonymous
  • anonymous
where is ur answer?
anonymous
  • anonymous
what did you get? And next time, i recommend you go to the Calculus section, not the math.
Jaweria
  • Jaweria
its \[2x /\sqrt{1-4x+25}\]
anonymous
  • anonymous
(2x+5)=cosy
anonymous
  • anonymous
-dy/dxsiny=2
anonymous
  • anonymous
dy/dx=-2/siny
Jaweria
  • Jaweria
oh so there wont be 2x anymore
anonymous
  • anonymous
yup correct ur error, u'll get used to the method by practicing
Jaweria
  • Jaweria
hmm ok
anonymous
  • anonymous
it's ok to make error because from them u learn, but don't get turned off because of errors and ur close in ur answer
anonymous
  • anonymous
ur not that far
Jaweria
  • Jaweria
ok i know that numerator will be 2 but under radical is that also wrong?
Jaweria
  • Jaweria
i m sorry i know i am asking too many stupid questions
anonymous
  • anonymous
no ask any qs u like there isn't a stupid question in maths
Jaweria
  • Jaweria
okyyy :)
anonymous
  • anonymous
ok let me surprise u
Jaweria
  • Jaweria
alright i m waiting for my surprise
anonymous
  • anonymous
|dw:1360124524210:dw|
anonymous
  • anonymous
can u solve the rest and tell me where did u make the mistake
Jaweria
  • Jaweria
alright i am
anonymous
  • anonymous
now ur final answer should be
anonymous
  • anonymous
\[\frac{ dy }{ dx }=\frac{ 1 }{ \sqrt{-x^2-5x-6} }\]
anonymous
  • anonymous
is the script clear because i am writing using a normal mouse
Jaweria
  • Jaweria
yeah thats fine
Jaweria
  • Jaweria
I m actually multiplying 2x by the power of 2 so its 4x and multipylinh 5 by the power of 2 so its giving me 25
anonymous
  • anonymous
by the way give me the other 2 equations so u try and i try to solve the problem
anonymous
  • anonymous
and this way we can save time
Jaweria
  • Jaweria
oh ok
Jaweria
  • Jaweria
but before I do that one more question just one last time can you please show me that how you got that answer on the numerator is 1 and denominator is different too.
Jaweria
  • Jaweria
just last time then after that I ll do my other 3
anonymous
  • anonymous
sure
Jaweria
  • Jaweria
thanks
anonymous
  • anonymous
|dw:1360125108009:dw|
anonymous
  • anonymous
|dw:1360125325494:dw|
anonymous
  • anonymous
can u see the answer now
anonymous
  • anonymous
r u there?
Jaweria
  • Jaweria
yeah sorry i was focusing deeply to that answer
Jaweria
  • Jaweria
sorry one more question
Jaweria
  • Jaweria
how you got 5 under that radical?
anonymous
  • anonymous
yup go ahead
Jaweria
  • Jaweria
bcoz once you took 4 out then 10 doesnt come into table of 4
anonymous
  • anonymous
sorry its 20 not 10
Jaweria
  • Jaweria
but how we are getting 20?
anonymous
  • anonymous
because (2x+5)^2= 4x^2 + 20x +25
anonymous
  • anonymous
and 25-1=24
anonymous
  • anonymous
4x^2+20x+24, 4(x^2+5x+6)
Jaweria
  • Jaweria
oh GOD whats wrong with me seriously my brain really isnt working I m still stuck with this 20
Jaweria
  • Jaweria
I m trying to figure out that how we got 20 it looks like I forgot basic math too
anonymous
  • anonymous
|dw:1360126122644:dw|
anonymous
  • anonymous
u haven't ur just feeling tired i know u r clever
Jaweria
  • Jaweria
yeah no doubt I m tired I had a classes today from 8:45am to 7:05 pm
Jaweria
  • Jaweria
thanks though
anonymous
  • anonymous
what's ur major?
Jaweria
  • Jaweria
Information Science
anonymous
  • anonymous
ok good
Jaweria
  • Jaweria
ok but once you will cancel that 2 out from denominator of 4, arent you not suppose to get 2 in denominator?
anonymous
  • anonymous
not because its root4=2
anonymous
  • anonymous
remember we took the 4 out of the root
Jaweria
  • Jaweria
\[1/2\sqrt{-x ^2{}}-5x-6\]
anonymous
  • anonymous
|dw:1360126668198:dw|
Jaweria
  • Jaweria
yeah we did take the 4 out from the root but we are also canceling that 2 with 4 right?
anonymous
  • anonymous
so u can see when we took the 16 out of the root it became 4
anonymous
  • anonymous
no cancelling the 2 with root4
Jaweria
  • Jaweria
oh ok
anonymous
  • anonymous
again let me show u
anonymous
  • anonymous
|dw:1360126822923:dw|
Jaweria
  • Jaweria
alright sir I got it now thank you so much for your patience and big help :)
Jaweria
  • Jaweria
I really appreciated
anonymous
  • anonymous
ur welcome
anonymous
  • anonymous
by the way how does this smart score work
anonymous
  • anonymous
and kindly send me the other 3 questions
Jaweria
  • Jaweria
oh I never worked on that smart score thing sorry
Jaweria
  • Jaweria
oh ok I will share with you these questions
Jaweria
  • Jaweria
\[Y=\arctan(\sqrt{cscx})\]
anonymous
  • anonymous
hehehe wow that is a long solution but not bad, with our method we can solve almost any question
Jaweria
  • Jaweria
\[Y=\sec ^{-1}(e ^{x2})\]
Jaweria
  • Jaweria
yeah
Jaweria
  • Jaweria
and one last question of this homework is: \[Y=arc \cot(\sec 5x ^{3})\]
anonymous
  • anonymous
that last function e^x^2 is how ur iphone works by the way
anonymous
  • anonymous
by the way i calculated all the answer in my head
Jaweria
  • Jaweria
lolz I dont have an iphone I carry that ordinary phones
anonymous
  • anonymous
now u really have some chain rules here u have to be accurate
Jaweria
  • Jaweria
hmm ok
Jaweria
  • Jaweria
seriously i m giving up now I cant do this anymore ;(
Jaweria
  • Jaweria
I m just so tired and again I have classes tomorrow frm 8:45 am and its all due tomorrow its already 12:22 am here
anonymous
  • anonymous
by the way u can use the tables
anonymous
  • anonymous
it would be faster
anonymous
  • anonymous
ok all the best
anonymous
  • anonymous
i will solve them for u
Jaweria
  • Jaweria
hmm I feel bad though but if you can I really appreciate it
anonymous
  • anonymous
its ok see u tomorrow
Jaweria
  • Jaweria
alright thank u soo much though for your help. :) take care bye.

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