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Jaweria

  • 2 years ago

Can anyone please help me with this question? Find Y prime: Y=cos^-1(2x+5).

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  1. Jaweria
    • 2 years ago
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    This is the equation: \[Y=\cos^{-1} (2x+5)\]

  2. Jaweria
    • 2 years ago
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    This is a new math to me and the homework is due tomorrow I m stuck with these problems!!

  3. Jaweria
    • 2 years ago
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    I got an answer but it looks weird

  4. mathsmind
    • 2 years ago
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    where is ur answer?

  5. rnick
    • 2 years ago
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    what did you get? And next time, i recommend you go to the Calculus section, not the math.

  6. Jaweria
    • 2 years ago
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    its \[2x /\sqrt{1-4x+25}\]

  7. mathsmind
    • 2 years ago
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    (2x+5)=cosy

  8. mathsmind
    • 2 years ago
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    -dy/dxsiny=2

  9. mathsmind
    • 2 years ago
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    dy/dx=-2/siny

  10. Jaweria
    • 2 years ago
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    oh so there wont be 2x anymore

  11. mathsmind
    • 2 years ago
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    yup correct ur error, u'll get used to the method by practicing

  12. Jaweria
    • 2 years ago
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    hmm ok

  13. mathsmind
    • 2 years ago
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    it's ok to make error because from them u learn, but don't get turned off because of errors and ur close in ur answer

  14. mathsmind
    • 2 years ago
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    ur not that far

  15. Jaweria
    • 2 years ago
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    ok i know that numerator will be 2 but under radical is that also wrong?

  16. Jaweria
    • 2 years ago
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    i m sorry i know i am asking too many stupid questions

  17. mathsmind
    • 2 years ago
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    no ask any qs u like there isn't a stupid question in maths

  18. Jaweria
    • 2 years ago
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    okyyy :)

  19. mathsmind
    • 2 years ago
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    ok let me surprise u

  20. Jaweria
    • 2 years ago
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    alright i m waiting for my surprise

  21. mathsmind
    • 2 years ago
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    |dw:1360124524210:dw|

  22. mathsmind
    • 2 years ago
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    can u solve the rest and tell me where did u make the mistake

  23. Jaweria
    • 2 years ago
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    alright i am

  24. mathsmind
    • 2 years ago
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    now ur final answer should be

  25. mathsmind
    • 2 years ago
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    \[\frac{ dy }{ dx }=\frac{ 1 }{ \sqrt{-x^2-5x-6} }\]

  26. mathsmind
    • 2 years ago
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    is the script clear because i am writing using a normal mouse

  27. Jaweria
    • 2 years ago
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    yeah thats fine

  28. Jaweria
    • 2 years ago
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    I m actually multiplying 2x by the power of 2 so its 4x and multipylinh 5 by the power of 2 so its giving me 25

  29. mathsmind
    • 2 years ago
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    by the way give me the other 2 equations so u try and i try to solve the problem

  30. mathsmind
    • 2 years ago
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    and this way we can save time

  31. Jaweria
    • 2 years ago
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    oh ok

  32. Jaweria
    • 2 years ago
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    but before I do that one more question just one last time can you please show me that how you got that answer on the numerator is 1 and denominator is different too.

  33. Jaweria
    • 2 years ago
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    just last time then after that I ll do my other 3

  34. mathsmind
    • 2 years ago
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    sure

  35. Jaweria
    • 2 years ago
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    thanks

  36. mathsmind
    • 2 years ago
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    |dw:1360125108009:dw|

  37. mathsmind
    • 2 years ago
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    |dw:1360125325494:dw|

  38. mathsmind
    • 2 years ago
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    can u see the answer now

  39. mathsmind
    • 2 years ago
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    r u there?

  40. Jaweria
    • 2 years ago
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    yeah sorry i was focusing deeply to that answer

  41. Jaweria
    • 2 years ago
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    sorry one more question

  42. Jaweria
    • 2 years ago
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    how you got 5 under that radical?

  43. mathsmind
    • 2 years ago
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    yup go ahead

  44. Jaweria
    • 2 years ago
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    bcoz once you took 4 out then 10 doesnt come into table of 4

  45. mathsmind
    • 2 years ago
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    sorry its 20 not 10

  46. Jaweria
    • 2 years ago
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    but how we are getting 20?

  47. mathsmind
    • 2 years ago
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    because (2x+5)^2= 4x^2 + 20x +25

  48. mathsmind
    • 2 years ago
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    and 25-1=24

  49. mathsmind
    • 2 years ago
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    4x^2+20x+24, 4(x^2+5x+6)

  50. Jaweria
    • 2 years ago
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    oh GOD whats wrong with me seriously my brain really isnt working I m still stuck with this 20

  51. Jaweria
    • 2 years ago
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    I m trying to figure out that how we got 20 it looks like I forgot basic math too

  52. mathsmind
    • 2 years ago
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    |dw:1360126122644:dw|

  53. mathsmind
    • 2 years ago
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    u haven't ur just feeling tired i know u r clever

  54. Jaweria
    • 2 years ago
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    yeah no doubt I m tired I had a classes today from 8:45am to 7:05 pm

  55. Jaweria
    • 2 years ago
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    thanks though

  56. mathsmind
    • 2 years ago
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    what's ur major?

  57. Jaweria
    • 2 years ago
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    Information Science

  58. mathsmind
    • 2 years ago
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    ok good

  59. Jaweria
    • 2 years ago
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    ok but once you will cancel that 2 out from denominator of 4, arent you not suppose to get 2 in denominator?

  60. mathsmind
    • 2 years ago
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    not because its root4=2

  61. mathsmind
    • 2 years ago
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    remember we took the 4 out of the root

  62. Jaweria
    • 2 years ago
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    \[1/2\sqrt{-x ^2{}}-5x-6\]

  63. mathsmind
    • 2 years ago
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    |dw:1360126668198:dw|

  64. Jaweria
    • 2 years ago
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    yeah we did take the 4 out from the root but we are also canceling that 2 with 4 right?

  65. mathsmind
    • 2 years ago
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    so u can see when we took the 16 out of the root it became 4

  66. mathsmind
    • 2 years ago
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    no cancelling the 2 with root4

  67. Jaweria
    • 2 years ago
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    oh ok

  68. mathsmind
    • 2 years ago
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    again let me show u

  69. mathsmind
    • 2 years ago
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    |dw:1360126822923:dw|

  70. Jaweria
    • 2 years ago
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    alright sir I got it now thank you so much for your patience and big help :)

  71. Jaweria
    • 2 years ago
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    I really appreciated

  72. mathsmind
    • 2 years ago
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    ur welcome

  73. mathsmind
    • 2 years ago
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    by the way how does this smart score work

  74. mathsmind
    • 2 years ago
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    and kindly send me the other 3 questions

  75. Jaweria
    • 2 years ago
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    oh I never worked on that smart score thing sorry

  76. Jaweria
    • 2 years ago
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    oh ok I will share with you these questions

  77. Jaweria
    • 2 years ago
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    \[Y=\arctan(\sqrt{cscx})\]

  78. mathsmind
    • 2 years ago
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    hehehe wow that is a long solution but not bad, with our method we can solve almost any question

  79. Jaweria
    • 2 years ago
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    \[Y=\sec ^{-1}(e ^{x2})\]

  80. Jaweria
    • 2 years ago
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    yeah

  81. Jaweria
    • 2 years ago
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    and one last question of this homework is: \[Y=arc \cot(\sec 5x ^{3})\]

  82. mathsmind
    • 2 years ago
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    that last function e^x^2 is how ur iphone works by the way

  83. mathsmind
    • 2 years ago
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    by the way i calculated all the answer in my head

  84. Jaweria
    • 2 years ago
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    lolz I dont have an iphone I carry that ordinary phones

  85. mathsmind
    • 2 years ago
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    now u really have some chain rules here u have to be accurate

  86. Jaweria
    • 2 years ago
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    hmm ok

  87. Jaweria
    • 2 years ago
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    seriously i m giving up now I cant do this anymore ;(

  88. Jaweria
    • 2 years ago
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    I m just so tired and again I have classes tomorrow frm 8:45 am and its all due tomorrow its already 12:22 am here

  89. mathsmind
    • 2 years ago
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    by the way u can use the tables

  90. mathsmind
    • 2 years ago
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    it would be faster

  91. mathsmind
    • 2 years ago
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    ok all the best

  92. mathsmind
    • 2 years ago
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    i will solve them for u

  93. Jaweria
    • 2 years ago
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    hmm I feel bad though but if you can I really appreciate it

  94. mathsmind
    • 2 years ago
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    its ok see u tomorrow

  95. Jaweria
    • 2 years ago
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    alright thank u soo much though for your help. :) take care bye.

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