Can anyone please help me with this question? Find Y prime: Y=cos^-1(2x+5).

- Jaweria

Can anyone please help me with this question? Find Y prime: Y=cos^-1(2x+5).

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- Jaweria

This is the equation: \[Y=\cos^{-1} (2x+5)\]

- Jaweria

This is a new math to me and the homework is due tomorrow I m stuck with these problems!!

- Jaweria

I got an answer but it looks weird

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## More answers

- anonymous

where is ur answer?

- anonymous

what did you get? And next time, i recommend you go to the Calculus section, not the math.

- Jaweria

its \[2x /\sqrt{1-4x+25}\]

- anonymous

(2x+5)=cosy

- anonymous

-dy/dxsiny=2

- anonymous

dy/dx=-2/siny

- Jaweria

oh so there wont be 2x anymore

- anonymous

yup correct ur error, u'll get used to the method by practicing

- Jaweria

hmm ok

- anonymous

it's ok to make error because from them u learn, but don't get turned off because of errors and ur close in ur answer

- anonymous

ur not that far

- Jaweria

ok i know that numerator will be 2 but under radical is that also wrong?

- Jaweria

i m sorry i know i am asking too many stupid questions

- anonymous

no ask any qs u like there isn't a stupid question in maths

- Jaweria

okyyy :)

- anonymous

ok let me surprise u

- Jaweria

alright i m waiting for my surprise

- anonymous

|dw:1360124524210:dw|

- anonymous

can u solve the rest and tell me where did u make the mistake

- Jaweria

alright i am

- anonymous

now ur final answer should be

- anonymous

\[\frac{ dy }{ dx }=\frac{ 1 }{ \sqrt{-x^2-5x-6} }\]

- anonymous

is the script clear because i am writing using a normal mouse

- Jaweria

yeah thats fine

- Jaweria

I m actually multiplying 2x by the power of 2 so its 4x and multipylinh 5 by the power of 2 so its giving me 25

- anonymous

by the way give me the other 2 equations so u try and i try to solve the problem

- anonymous

and this way we can save time

- Jaweria

oh ok

- Jaweria

but before I do that one more question just one last time can you please show me that how you got that answer on the numerator is 1 and denominator is different too.

- Jaweria

just last time then after that I ll do my other 3

- anonymous

sure

- Jaweria

thanks

- anonymous

|dw:1360125108009:dw|

- anonymous

|dw:1360125325494:dw|

- anonymous

can u see the answer now

- anonymous

r u there?

- Jaweria

yeah sorry i was focusing deeply to that answer

- Jaweria

sorry one more question

- Jaweria

how you got 5 under that radical?

- anonymous

yup go ahead

- Jaweria

bcoz once you took 4 out then 10 doesnt come into table of 4

- anonymous

sorry its 20 not 10

- Jaweria

but how we are getting 20?

- anonymous

because (2x+5)^2= 4x^2 + 20x +25

- anonymous

and 25-1=24

- anonymous

4x^2+20x+24, 4(x^2+5x+6)

- Jaweria

oh GOD whats wrong with me seriously my brain really isnt working I m still stuck with this 20

- Jaweria

I m trying to figure out that how we got 20 it looks like I forgot basic math too

- anonymous

|dw:1360126122644:dw|

- anonymous

u haven't ur just feeling tired i know u r clever

- Jaweria

yeah no doubt I m tired I had a classes today from 8:45am to 7:05 pm

- Jaweria

thanks though

- anonymous

what's ur major?

- Jaweria

Information Science

- anonymous

ok good

- Jaweria

ok but once you will cancel that 2 out from denominator of 4, arent you not suppose to get 2 in denominator?

- anonymous

not because its root4=2

- anonymous

remember we took the 4 out of the root

- Jaweria

\[1/2\sqrt{-x ^2{}}-5x-6\]

- anonymous

|dw:1360126668198:dw|

- Jaweria

yeah we did take the 4 out from the root but we are also canceling that 2 with 4 right?

- anonymous

so u can see when we took the 16 out of the root it became 4

- anonymous

no cancelling the 2 with root4

- Jaweria

oh ok

- anonymous

again let me show u

- anonymous

|dw:1360126822923:dw|

- Jaweria

alright sir I got it now thank you so much for your patience and big help :)

- Jaweria

I really appreciated

- anonymous

ur welcome

- anonymous

by the way how does this smart score work

- anonymous

and kindly send me the other 3 questions

- Jaweria

oh I never worked on that smart score thing sorry

- Jaweria

oh ok I will share with you these questions

- Jaweria

\[Y=\arctan(\sqrt{cscx})\]

- anonymous

hehehe wow that is a long solution but not bad, with our method we can solve almost any question

- Jaweria

\[Y=\sec ^{-1}(e ^{x2})\]

- Jaweria

yeah

- Jaweria

and one last question of this homework is: \[Y=arc \cot(\sec 5x ^{3})\]

- anonymous

that last function e^x^2 is how ur iphone works by the way

- anonymous

by the way i calculated all the answer in my head

- Jaweria

lolz I dont have an iphone I carry that ordinary phones

- anonymous

now u really have some chain rules here u have to be accurate

- Jaweria

hmm ok

- Jaweria

seriously i m giving up now I cant do this anymore ;(

- Jaweria

I m just so tired and again I have classes tomorrow frm 8:45 am and its all due tomorrow its already 12:22 am here

- anonymous

by the way u can use the tables

- anonymous

it would be faster

- anonymous

ok all the best

- anonymous

i will solve them for u

- Jaweria

hmm I feel bad though but if you can I really appreciate it

- anonymous

its ok see u tomorrow

- Jaweria

alright thank u soo much though for your help. :) take care bye.

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