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Anita505
Group Title
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was..
A) Replaced before the second draw
B) NOT replaced before the second draw
a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.
 one year ago
 one year ago
Anita505 Group Title
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was.. A) Replaced before the second draw B) NOT replaced before the second draw a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.
 one year ago
 one year ago

This Question is Closed

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
I know the solution...
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
Can you please help me?
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Section A) Consider the following 3 situations: (1) A: First ball red B: Second ball red The events A and B are independent therefore P(two red) = (5/10) * (5/10) ...........................(1) (2) A: First ball red B: Second ball black The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(2) (3) A: First ball black B: Second ball red The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(3) The probability that at least 1 ball was red, given that the first ball was replaced before the second draw is the sum of results (1), (2) and (3). Can you calculate?
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
Sorry i can not calculate it,
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
my calculator is currently not working
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
so this is what it would look like then (5/10)(5/10)+(5/10)(5/10)+(5/10)(5/10)=
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
You do not need a calculator to work this out: \[P(at\ least\ one\ red)=(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})=?\]
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Hint: \[\frac{5}{10}\times \frac{5}{10}=\frac{1}{2}\times \frac{1}{2}\]
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
so the answer would be 0.75
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Good work! Your answer is correct.
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
oops no sorry my mistake
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
0.75 or 3/4 is correct.
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
How would i find the probability that at least 1 ball was red, given that the first ball s not replaced before the second draw?
 one year ago

teddyt477 Group TitleBest ResponseYou've already chosen the best response.0
take the chance after by subtracting out already drawn balls
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Section B) Probability first ball is red = 5/10 Probability second ball is red = 4/9 P(two red) = (5/10 * 4/9) ................(1) Probability first ball is red = 5/10 Probability second ball is black = 5/9 P(one red) = (5/10 * 5/9) ...............(2) Probability first ball is black = 5/10 Probability second ball is red = 5/9 P(one red) = (5/10 * 5/9) ...............(3) \[P(at\ least\ one\ red)=(\frac{1}{2}\times \frac{4}{9})+(\frac{1}{2}\times \frac{5}{9})+(\frac{1}{2}\times \frac{5}{9})=?\]
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
thank you and the answer i have recieved was 0.77777777777
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
is that also what you got?
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Your answer to B) is correct. Good work :)
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
thank you for your help! :)
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
but should i put my answer as 0.78?
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
it says to simply my answer into a integer or fraction
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
simplify**
 one year ago

Anita505 Group TitleBest ResponseYou've already chosen the best response.0
oops nvm its 7/9 hahaha thanks!
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
To put the answer as a fraction just add the following fractions and simplify: \[\frac{4}{18}+\frac{5}{18}+\frac{5}{18}=?\]
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
Yes, 7/9 is correct!
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
You're welcome :)
 one year ago
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