A community for students.
Here's the question you clicked on:
 0 viewing
Anita505
 3 years ago
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was..
A) Replaced before the second draw
B) NOT replaced before the second draw
a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.
Anita505
 3 years ago
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was.. A) Replaced before the second draw B) NOT replaced before the second draw a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.

This Question is Closed

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0I know the solution...

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0Can you please help me?

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Section A) Consider the following 3 situations: (1) A: First ball red B: Second ball red The events A and B are independent therefore P(two red) = (5/10) * (5/10) ...........................(1) (2) A: First ball red B: Second ball black The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(2) (3) A: First ball black B: Second ball red The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(3) The probability that at least 1 ball was red, given that the first ball was replaced before the second draw is the sum of results (1), (2) and (3). Can you calculate?

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry i can not calculate it,

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0my calculator is currently not working

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0so this is what it would look like then (5/10)(5/10)+(5/10)(5/10)+(5/10)(5/10)=

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0You do not need a calculator to work this out: \[P(at\ least\ one\ red)=(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})=?\]

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Hint: \[\frac{5}{10}\times \frac{5}{10}=\frac{1}{2}\times \frac{1}{2}\]

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0so the answer would be 0.75

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Good work! Your answer is correct.

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0oops no sorry my mistake

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.00.75 or 3/4 is correct.

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0How would i find the probability that at least 1 ball was red, given that the first ball s not replaced before the second draw?

teddyt477
 3 years ago
Best ResponseYou've already chosen the best response.0take the chance after by subtracting out already drawn balls

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Section B) Probability first ball is red = 5/10 Probability second ball is red = 4/9 P(two red) = (5/10 * 4/9) ................(1) Probability first ball is red = 5/10 Probability second ball is black = 5/9 P(one red) = (5/10 * 5/9) ...............(2) Probability first ball is black = 5/10 Probability second ball is red = 5/9 P(one red) = (5/10 * 5/9) ...............(3) \[P(at\ least\ one\ red)=(\frac{1}{2}\times \frac{4}{9})+(\frac{1}{2}\times \frac{5}{9})+(\frac{1}{2}\times \frac{5}{9})=?\]

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0thank you and the answer i have recieved was 0.77777777777

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0is that also what you got?

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0Your answer to B) is correct. Good work :)

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0thank you for your help! :)

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0but should i put my answer as 0.78?

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0it says to simply my answer into a integer or fraction

Anita505
 3 years ago
Best ResponseYou've already chosen the best response.0oops nvm its 7/9 hahaha thanks!

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0To put the answer as a fraction just add the following fractions and simplify: \[\frac{4}{18}+\frac{5}{18}+\frac{5}{18}=?\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.