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 one year ago
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was..
A) Replaced before the second draw
B) NOT replaced before the second draw
a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.
 one year ago
Two balls are drawn in succession out of a box containing 5 red and 5 white balls. Find the probability that at least 1 ball was red, given that the first ball was.. A) Replaced before the second draw B) NOT replaced before the second draw a) Find the probability that at least 1 ball was red, given that the first ball was replaced before the second draw.

This Question is Closed

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0I know the solution...

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0Can you please help me?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Section A) Consider the following 3 situations: (1) A: First ball red B: Second ball red The events A and B are independent therefore P(two red) = (5/10) * (5/10) ...........................(1) (2) A: First ball red B: Second ball black The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(2) (3) A: First ball black B: Second ball red The events A and B are independent therefore P(one red) = (5/10) * (5/10) ...........................(3) The probability that at least 1 ball was red, given that the first ball was replaced before the second draw is the sum of results (1), (2) and (3). Can you calculate?

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0Sorry i can not calculate it,

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0my calculator is currently not working

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0so this is what it would look like then (5/10)(5/10)+(5/10)(5/10)+(5/10)(5/10)=

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0You do not need a calculator to work this out: \[P(at\ least\ one\ red)=(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})+(\frac{5}{10}\times \frac{5}{10})=?\]

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Hint: \[\frac{5}{10}\times \frac{5}{10}=\frac{1}{2}\times \frac{1}{2}\]

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be 0.75

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Good work! Your answer is correct.

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0oops no sorry my mistake

kropot72
 one year ago
Best ResponseYou've already chosen the best response.00.75 or 3/4 is correct.

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0How would i find the probability that at least 1 ball was red, given that the first ball s not replaced before the second draw?

teddyt477
 one year ago
Best ResponseYou've already chosen the best response.0take the chance after by subtracting out already drawn balls

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Section B) Probability first ball is red = 5/10 Probability second ball is red = 4/9 P(two red) = (5/10 * 4/9) ................(1) Probability first ball is red = 5/10 Probability second ball is black = 5/9 P(one red) = (5/10 * 5/9) ...............(2) Probability first ball is black = 5/10 Probability second ball is red = 5/9 P(one red) = (5/10 * 5/9) ...............(3) \[P(at\ least\ one\ red)=(\frac{1}{2}\times \frac{4}{9})+(\frac{1}{2}\times \frac{5}{9})+(\frac{1}{2}\times \frac{5}{9})=?\]

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0thank you and the answer i have recieved was 0.77777777777

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0is that also what you got?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0Your answer to B) is correct. Good work :)

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0thank you for your help! :)

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0but should i put my answer as 0.78?

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0it says to simply my answer into a integer or fraction

Anita505
 one year ago
Best ResponseYou've already chosen the best response.0oops nvm its 7/9 hahaha thanks!

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0To put the answer as a fraction just add the following fractions and simplify: \[\frac{4}{18}+\frac{5}{18}+\frac{5}{18}=?\]
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