Here's the question you clicked on:
charlotte123
Choose the equation of the line passing through the point (-1, -2) and perpendicular to y = 1/4x + 2. y = 4x - 6 y = -4x - 6 y = -4x + 2 y = 4x
For two lines to be perpendicular, the product of their slopes must equal -1. The known line is in the slope-intercept form: \(y = mx + b\) where \(m\) is the slope and \(b\) is the y-value of the y-intercept. Use the slope to find the slope of the perpendicular line. Then use the known point to find the value of \(b\) for the perpendicular line.
@whpalmer4 so would the answer be a? :P
Well, what's the slope of the known line, and what's the slope of the line in a)? If you multiply them together, what do you get?
wait a sec I got this wrong >.> can u help me out? :(
That's why I'm here :-)
XD so how do I start? :) this is a pretest, so I dont really know how to solve it or anything D:
Okay, look at my first post, where I describe the slope-intercept form. Now look at the equation in the question, and compare them. What is the coefficient of x in the equation? That will be the slope of the line.
(the original line, that is)