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charlotte123

  • 3 years ago

Choose the equation of the line passing through the point (-1, -2) and perpendicular to y = 1/4x + 2. y = 4x - 6 y = -4x - 6 y = -4x + 2 y = 4x

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  1. whpalmer4
    • 3 years ago
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    For two lines to be perpendicular, the product of their slopes must equal -1. The known line is in the slope-intercept form: \(y = mx + b\) where \(m\) is the slope and \(b\) is the y-value of the y-intercept. Use the slope to find the slope of the perpendicular line. Then use the known point to find the value of \(b\) for the perpendicular line.

  2. charlotte123
    • 3 years ago
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    @whpalmer4 so would the answer be a? :P

  3. whpalmer4
    • 3 years ago
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    Well, what's the slope of the known line, and what's the slope of the line in a)? If you multiply them together, what do you get?

  4. charlotte123
    • 3 years ago
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    wait a sec I got this wrong >.> can u help me out? :(

  5. whpalmer4
    • 3 years ago
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    That's why I'm here :-)

  6. charlotte123
    • 3 years ago
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    XD so how do I start? :) this is a pretest, so I dont really know how to solve it or anything D:

  7. whpalmer4
    • 3 years ago
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    Okay, look at my first post, where I describe the slope-intercept form. Now look at the equation in the question, and compare them. What is the coefficient of x in the equation? That will be the slope of the line.

  8. whpalmer4
    • 3 years ago
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    (the original line, that is)

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