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geerky42 Group Title

Physics -> Rotation Help Needed! (see attachment)

  • one year ago
  • one year ago

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  1. geerky42 Group Title
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    • one year ago
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  2. shubhamsrg Group Title
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    |dw:1360138607944:dw|

    • one year ago
  3. geerky42 Group Title
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    Ok, and?

    • one year ago
  4. shubhamsrg Group Title
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    where are you stuck ?

    • one year ago
  5. shubhamsrg Group Title
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    |dw:1360138848396:dw|

    • one year ago
  6. geerky42 Group Title
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    On torque. I don't know how to find torque.

    • one year ago
  7. geerky42 Group Title
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    \(\tau = F_\perp r\) , right?

    • one year ago
  8. shubhamsrg Group Title
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    mg(3) = I (alpha)

    • one year ago
  9. geerky42 Group Title
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    I don't understand exactly what this formula means.

    • one year ago
  10. shubhamsrg Group Title
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    I will be around the point where it is pivoted

    • one year ago
  11. shubhamsrg Group Title
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    See its equivalent to F=ma

    • one year ago
  12. shubhamsrg Group Title
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    here its torque = I alpha

    • one year ago
  13. shubhamsrg Group Title
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    Can you calculate moment of inertia about the point where it is pivoted?

    • one year ago
  14. geerky42 Group Title
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    \[I = \dfrac{1}{3}m(6^2)\]Right?

    • one year ago
  15. shubhamsrg Group Title
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    RIght.

    • one year ago
  16. geerky42 Group Title
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    Ok, just checking. I'm starting to understand a little bit. Thanks.

    • one year ago
  17. shubhamsrg Group Title
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    So mg(3) = I (alpha) simply calculate alpha

    • one year ago
  18. geerky42 Group Title
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    Yeah, I got it.

    • one year ago
  19. shubhamsrg Group Title
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    Glad you did.

    • one year ago
  20. shubhamsrg Group Title
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    Its all pretty similar to linear motion, just write net toruqe = I alpha

    • one year ago
  21. geerky42 Group Title
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    Ok, One more question. How can you find torque in this system?

    • one year ago
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  22. geerky42 Group Title
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    @shubhamsrg

    • one year ago
  23. shubhamsrg Group Title
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    Sorry for the late reply, was busy somewhere.

    • one year ago
  24. shubhamsrg Group Title
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    So whats your progress in this ?

    • one year ago
  25. geerky42 Group Title
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    I just need to do the same: find the angular acceleration. I'm not sure what to do with torque. I don't know how to find \(F_\perp\).

    • one year ago
  26. shubhamsrg Group Title
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    |dw:1360140460045:dw|

    • one year ago
  27. geerky42 Group Title
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    Can you be a little more clarity?

    • one year ago
  28. shubhamsrg Group Title
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    I remains same, right ?

    • one year ago
  29. geerky42 Group Title
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    Right.

    • one year ago
  30. geerky42 Group Title
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    But torque isn't, right?

    • one year ago
  31. shubhamsrg Group Title
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    perpendicular distance changes

    • one year ago
  32. shubhamsrg Group Title
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    |dw:1360140731467:dw|

    • one year ago
  33. shubhamsrg Group Title
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    x is the new distance. our eqn will be mgx = I alpha

    • one year ago
  34. geerky42 Group Title
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    Ah, thanks!

    • one year ago
  35. shubhamsrg Group Title
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    hmm.

    • one year ago
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