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shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1360138607944:dw
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
where are you stuck ?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1360138848396:dw
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
On torque. I don't know how to find torque.
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
\(\tau = F_\perp r\) , right?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
mg(3) = I (alpha)
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
I don't understand exactly what this formula means.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
I will be around the point where it is pivoted
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
See its equivalent to F=ma
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
here its torque = I alpha
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
Can you calculate moment of inertia about the point where it is pivoted?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
\[I = \dfrac{1}{3}m(6^2)\]Right?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Ok, just checking. I'm starting to understand a little bit. Thanks.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
So mg(3) = I (alpha) simply calculate alpha
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Yeah, I got it.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
Glad you did.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
Its all pretty similar to linear motion, just write net toruqe = I alpha
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Ok, One more question. How can you find torque in this system?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
@shubhamsrg
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
Sorry for the late reply, was busy somewhere.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
So whats your progress in this ?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
I just need to do the same: find the angular acceleration. I'm not sure what to do with torque. I don't know how to find \(F_\perp\).
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1360140460045:dw
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Can you be a little more clarity?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
I remains same, right ?
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
But torque isn't, right?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
perpendicular distance changes
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1360140731467:dw
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
x is the new distance. our eqn will be mgx = I alpha
 one year ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.1
Ah, thanks!
 one year ago
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