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shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360138607944:dw

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1where are you stuck ?

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360138848396:dw

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1On torque. I don't know how to find torque.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\(\tau = F_\perp r\) , right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I don't understand exactly what this formula means.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1I will be around the point where it is pivoted

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1See its equivalent to F=ma

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1here its torque = I alpha

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1Can you calculate moment of inertia about the point where it is pivoted?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\[I = \dfrac{1}{3}m(6^2)\]Right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Ok, just checking. I'm starting to understand a little bit. Thanks.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1So mg(3) = I (alpha) simply calculate alpha

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1Its all pretty similar to linear motion, just write net toruqe = I alpha

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Ok, One more question. How can you find torque in this system?

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1Sorry for the late reply, was busy somewhere.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1So whats your progress in this ?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I just need to do the same: find the angular acceleration. I'm not sure what to do with torque. I don't know how to find \(F_\perp\).

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360140460045:dw

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Can you be a little more clarity?

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1I remains same, right ?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1But torque isn't, right?

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1perpendicular distance changes

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360140731467:dw

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.1x is the new distance. our eqn will be mgx = I alpha
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