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geerky42
 3 years ago
Physics > Rotation
Help Needed! (see attachment)
geerky42
 3 years ago
Physics > Rotation Help Needed! (see attachment)

This Question is Closed

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360138607944:dw

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1where are you stuck ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360138848396:dw

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1On torque. I don't know how to find torque.

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1\(\tau = F_\perp r\) , right?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1I don't understand exactly what this formula means.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1I will be around the point where it is pivoted

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1See its equivalent to F=ma

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1here its torque = I alpha

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Can you calculate moment of inertia about the point where it is pivoted?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1\[I = \dfrac{1}{3}m(6^2)\]Right?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1Ok, just checking. I'm starting to understand a little bit. Thanks.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1So mg(3) = I (alpha) simply calculate alpha

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Its all pretty similar to linear motion, just write net toruqe = I alpha

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1Ok, One more question. How can you find torque in this system?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry for the late reply, was busy somewhere.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1So whats your progress in this ?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1I just need to do the same: find the angular acceleration. I'm not sure what to do with torque. I don't know how to find \(F_\perp\).

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360140460045:dw

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1Can you be a little more clarity?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1I remains same, right ?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.1But torque isn't, right?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1perpendicular distance changes

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360140731467:dw

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1x is the new distance. our eqn will be mgx = I alpha
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