anonymous
  • anonymous
...
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
you need to factor the denominator to determine this
amistre64
  • amistre64
just at a cursory glance; 5 would not be able to produce a VA, only a hole.
anonymous
  • anonymous
Ok its driving me crazy. I know what factoring the denominator is, but i just cant remember how to do it.

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amistre64
  • amistre64
:) it takes a little practice; but let me go with the definition of a hole. the only time we get a whole is of the top and bottom have common factors. Since the only factor up top is (x-5), the only possible hole that can be produced is when x=5 since that zeros it out. no option tells us a hole at x=5
amistre64
  • amistre64
therefore, my gut says there are no holes and only one option calls for that. but this is just gut talking
anonymous
  • anonymous
Ok. Thanks! :)

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