anonymous
  • anonymous
The moment of inertia of a thin sheet of mass m and radius R about AB ?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1360165380404:dw|
JamesJ
  • JamesJ
Use the parallel axis theorem
anonymous
  • anonymous
I (AB) = I (CM) + m * perpendicular Distance

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anonymous
  • anonymous
Ryt
JamesJ
  • JamesJ
in other words, start with the moment of inertia of the disc rotated through an axis running through the center of the disc, then apply the theorem to shift the rotation axis.
JamesJ
  • JamesJ
Yes
anonymous
  • anonymous
so mR^2 /4 + m R^2
anonymous
  • anonymous
@JamesJ ??
JamesJ
  • JamesJ
No, the moment of inertia rotating a disc about its center axis is mR^2/16
anonymous
  • anonymous
So..wat is ur answer
anonymous
  • anonymous
17mR^2 / 16
anonymous
  • anonymous
@JamesJ
JamesJ
  • JamesJ
Whats the perpendicular distance between the CM and the axis in this problem?
anonymous
  • anonymous
R
JamesJ
  • JamesJ
No, the *perpendicular* distance
JamesJ
  • JamesJ
|dw:1360168373543:dw|
anonymous
  • anonymous
|dw:1360168379873:dw|
JamesJ
  • JamesJ
We want the distance which is perpendicular to the axis of rotation, as I shown on my diagram
anonymous
  • anonymous
Ok..i got it nw.....Thxxxx a lot
anonymous
  • anonymous
Yup..i got it

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