Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Determine all horizontal, slant, and vertical asymptotes. For each vertical asymptote, determine whether f(x) > infinity sign of f(x) > negative infinity sign on either side of the asymptote.
 one year ago
 one year ago
Determine all horizontal, slant, and vertical asymptotes. For each vertical asymptote, determine whether f(x) > infinity sign of f(x) > negative infinity sign on either side of the asymptote.
 one year ago
 one year ago

This Question is Closed

satellite73Best ResponseYou've already chosen the best response.1
is it \[\frac{x^2}{4x^2}\]?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
ok so for the vertical asymptotes, set the denominator equal to zero and solve for \(x\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you get \[4x^2=0\] or \[(2x)(2+x)=0\] and the solutions are \(x=2\) or \(x=2\) those are your vertical asymptotes (there are two of them)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
for the horizontal asymptote, note that the numerator and denominator have the same degree (both are degree 2) so it is the ratio of the leading coefficients
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
the leading coefficient of \(x^2\) is 1 and the leading coefficient of \(4x^2\) is \(1\) therefore the horizontal asymptote is \(y=1\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
that is in the case where the degrees are the same. there is no slant asymptote for there to be a slant asymptote , the degree of the numerator would have to be one more than the degree of the denominator
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.