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anonymous
 3 years ago
Four rods of equal mass m each , Ab , BC , CA , DB are placed as shown. The moment of inertia of the system about B perpendicular to the plane ABC is (AB=a)
anonymous
 3 years ago
Four rods of equal mass m each , Ab , BC , CA , DB are placed as shown. The moment of inertia of the system about B perpendicular to the plane ABC is (AB=a)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360169550988:dw

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.0Obviously break down the problem rod by rod.

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.0And if you're really stuck, you're just going to integrate rod by rod.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I (BC) = ma^2/6 ryt ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Its basically a maths ques, you just need to find rod lengths, after doing that you just have to calculate moment of inertia of each rod about B and add all

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yup . i Have Calculated the length of rods BC = a/sqrt(2) , AC = a/sqrt(2) , DB = (sqrt2) * a / sqrt3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I (BC) = ma^2/6 ryt ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1won' that be (2/9)ma^2

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360246728479:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I (DB) = M L^2 / 3 * sin^2 30 ryt ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360246891927:dw

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1I don;t think angle matters

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1For calculation of I,

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Because the axis is perpendicular to plane, the rod will make 90 degrees with the axis, doesn't matter how it is placed.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1Do you have the final ans ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1<Lets see if we get that by my method>

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1And AC = ma^2/6 + 3ma^2/6 = 2ma^2 /3

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1So sum = ma^2 (2/3 + 2/9 + 1/6) = 19/18ma^2

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1hmm, okay doesn't match

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think that angle matters

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1AB = ma^2 /3 Sum = 25/18

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But Hw Did u Claculate I (AC) ??

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1calculate about C, then B

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.1"Angle will not matter here" ;)
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