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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
how long is the given vector to begin with?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
vector = L units to determine the vector of 1 unit, divide both sides by L vector/L = L/L units vector/L = 1 units
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
we just have the direction and the length of the required vector
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
thats all we need, and some knowledge about what a unit vector is spose to be ....
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
i have idea like: unit vector of that direction is <2, 1, 2>/sqr(2^2 +1^2+(2)^2 =<2/sqr(5,1/sqr(5),2/sqr(5)> is is right?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
thats correct :) except maybe check you length again
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
and use the length 1 multiply to the unit vector to get what we need, is it right?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
sqrt(8) = 2sqrt(2)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
ugh ... 4+1+4 = 9 so sqrt(9) = 3
 one year ago

Hoa Group TitleBest ResponseYou've already chosen the best response.0
yeah, you are right, my bad. thanks a lot
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
divide all the vector parts by 3 :)
 one year ago
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