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Hoa

  • 3 years ago

find a vector in the direction 2i+j-2k that has length 1

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  1. amistre64
    • 3 years ago
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    how long is the given vector to begin with?

  2. amistre64
    • 3 years ago
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    vector = L units to determine the vector of 1 unit, divide both sides by L vector/L = L/L units vector/L = 1 units

  3. Hoa
    • 3 years ago
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    we just have the direction and the length of the required vector

  4. amistre64
    • 3 years ago
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    thats all we need, and some knowledge about what a unit vector is spose to be ....

  5. Hoa
    • 3 years ago
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    i have idea like: unit vector of that direction is <2, 1, -2>/sqr(2^2 +1^2+(-2)^2 =<2/sqr(5,1/sqr(5),-2/sqr(5)> is is right?

  6. amistre64
    • 3 years ago
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    thats correct :) except maybe check you length again

  7. Hoa
    • 3 years ago
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    and use the length 1 multiply to the unit vector to get what we need, is it right?

  8. amistre64
    • 3 years ago
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    sqrt(8) = 2sqrt(2)

  9. amistre64
    • 3 years ago
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    ugh ... 4+1+4 = 9 so sqrt(9) = 3

  10. Hoa
    • 3 years ago
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    yeah, you are right, my bad. thanks a lot

  11. amistre64
    • 3 years ago
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    divide all the vector parts by 3 :)

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