A community for students.
Here's the question you clicked on:
 0 viewing
Hoa
 3 years ago
find a vector in the direction 2i+j2k that has length 1
Hoa
 3 years ago
find a vector in the direction 2i+j2k that has length 1

This Question is Closed

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1how long is the given vector to begin with?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1vector = L units to determine the vector of 1 unit, divide both sides by L vector/L = L/L units vector/L = 1 units

Hoa
 3 years ago
Best ResponseYou've already chosen the best response.0we just have the direction and the length of the required vector

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1thats all we need, and some knowledge about what a unit vector is spose to be ....

Hoa
 3 years ago
Best ResponseYou've already chosen the best response.0i have idea like: unit vector of that direction is <2, 1, 2>/sqr(2^2 +1^2+(2)^2 =<2/sqr(5,1/sqr(5),2/sqr(5)> is is right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1thats correct :) except maybe check you length again

Hoa
 3 years ago
Best ResponseYou've already chosen the best response.0and use the length 1 multiply to the unit vector to get what we need, is it right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1ugh ... 4+1+4 = 9 so sqrt(9) = 3

Hoa
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, you are right, my bad. thanks a lot

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1divide all the vector parts by 3 :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.