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EmmaH
 3 years ago
Solve by factoring: 3x^2 + 2x  1 = 0
{1, 2/3}
{1, 2/3}
{1, 1/3}
{1, 1/3}
EmmaH
 3 years ago
Solve by factoring: 3x^2 + 2x  1 = 0 {1, 2/3} {1, 2/3} {1, 1/3} {1, 1/3}

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EmmaH
 3 years ago
Best ResponseYou've already chosen the best response.0please explain how i find this

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.0well, dividing first by 3, we have \[ x^2 + \frac{2}{3}x  \frac{1}{3} = 0 \] Now, you want factors of 1/3 that add up to 2/3

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1@EmmaH, the steps for solving this are the same as what I showed you in the previous problem.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1I'll even give you a hint, but you have to solve the rest yourself: Given: \(3x^2 + 2x  1\) Split the middle term: \(3x^2 + 3x  1x  1\) Now factor by grouping

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Okay, now what's the next step?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Do you know how to factor \(3x^2 + 3x\) ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, or simply 3x(x + 1) Writing 1 before the x is not necessary. Now factor (1x  1). Let me know what you get.

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.0Well, you have a factor of (x+1) above where you wrote 3x(x+1) Can you get a factor of (x+1) out of (1x  1) ?
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