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I've tried working this problem on my own but it seems I am not getting it. I think I have the right idea, though. But, I could be way wrong still. :(
 one year ago
 one year ago
I've tried working this problem on my own but it seems I am not getting it. I think I have the right idea, though. But, I could be way wrong still. :(
 one year ago
 one year ago

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P.nut1996Best ResponseYou've already chosen the best response.0
What is the vertex of the graph of \[y=4(x+2)^2+5\]
 one year ago

HeroBest ResponseYou've already chosen the best response.1
What do you believe is the correct vertex of the graph?
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
A. (2,5) B. (2,5) C. (5,2) D. (5,2) I keep getting a negative 60 something for Y. Obviously that is not right. I haven't tried solving for x yet. Should I solve for x first maybe? :(
 one year ago

HeroBest ResponseYou've already chosen the best response.1
You don't need to solve for anything. You just need to know what to look for. The general vertex form of a parabola is: \(a(x  h)^2 + k\) where \((h,k)\) is the vertex. @jerry_5594, incorrect.
 one year ago
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