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P.nut1996

  • 2 years ago

I've tried working this problem on my own but it seems I am not getting it. I think I have the right idea, though. But, I could be way wrong still. :(

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  1. P.nut1996
    • 2 years ago
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    What is the vertex of the graph of \[y=-4(x+2)^2+5\]

  2. Hero
    • 2 years ago
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    What do you believe is the correct vertex of the graph?

  3. P.nut1996
    • 2 years ago
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    A. (2,5) B. (-2,5) C. (5,-2) D. (5,2) I keep getting a negative 60 something for Y. Obviously that is not right. I haven't tried solving for x yet. Should I solve for x first maybe? :(

  4. Hero
    • 2 years ago
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    You don't need to solve for anything. You just need to know what to look for. The general vertex form of a parabola is: \(a(x - h)^2 + k\) where \((h,k)\) is the vertex. @jerry_5594, incorrect.

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spraguer (Moderator)
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