A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
I've tried working this problem on my own but it seems I am not getting it. I think I have the right idea, though. But, I could be way wrong still. :(
 one year ago
I've tried working this problem on my own but it seems I am not getting it. I think I have the right idea, though. But, I could be way wrong still. :(

This Question is Closed

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0What is the vertex of the graph of \[y=4(x+2)^2+5\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.1What do you believe is the correct vertex of the graph?

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0A. (2,5) B. (2,5) C. (5,2) D. (5,2) I keep getting a negative 60 something for Y. Obviously that is not right. I haven't tried solving for x yet. Should I solve for x first maybe? :(

Hero
 one year ago
Best ResponseYou've already chosen the best response.1You don't need to solve for anything. You just need to know what to look for. The general vertex form of a parabola is: \(a(x  h)^2 + k\) where \((h,k)\) is the vertex. @jerry_5594, incorrect.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.