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anonymous
 3 years ago
matrix multiplication
anonymous
 3 years ago
matrix multiplication

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0comp being slow, pls wait..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok what is the matrix problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let x be an arbitrary angle and C represents cosine, S represent Sine

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and what are the dimensions of those matrices

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0matrix A= CX SX 0 aCX SX CX 0 aSX 0 0 1 0 0 0 0 1 matrix B= CY SY 0 bCY SY CY 0 bSY 0 0 1 0 0 0 0 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and Y another arbitrary angle..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think i get how to do the multiplication but since there are variables, i'm coming up with crazy figures for each new element in the new matrix. and this new matrix has to be multiplied by another 4x4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i guess my problem is more towards trig...is there a simple expressions for each element?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i will solve for u as soon as i am done with the other student

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thx, or you can just tell me if there's no simple expression cuz i can do all the work, it will just look messy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04x4 is a messy matrix, so should expect such a mess

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. or are you familiar with matlab? from what i remember, you have to have values for matlab...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do u want to do this with matlab or using normal mathematical methods

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's just part of the actual problem so i don't think working it out by hand is important so if i can do it on matlab, it would be great

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i will do it for u with c++ or c sharp

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so u just want to multiply those two matrices

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm not familiar with c++ but there is another matrix, i will type it up..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Matrix C= CZ SZ 0 cCZ SZ CZ 0 cSZ 0 0 1 0 0 0 0 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and a,b,c are arbitrary constants. so in c++, you can keep the expression with variables?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if that means the same thing as AxB=AB ABxC=result 4x4 matrix

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no it does not mean the same thing but i get what u want now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0am sorry of the delay just someone before u sent me a bunch of questions that i need to type the answers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so u can do others stuff and i will finish the work for u as soon as possible

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's fine, i will check later

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry for keeping u waiting but i need to know do u want element by element multiplication or linear algebraic product

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to be precise on that so i can give u the right answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0good question, i was actually trying to figure out on google. all the instructor said was to multiply them. what i found on google was this http://easycalculation.com/matrix/learnmatrixmultiplication.php which is what's going to make the result matrix look real messy. the problem is to find the transformation matrix of a mechanical grabber. so it would have multiple joints, point O as fixed, and point P as the position of the grabber. to find the position, find transformation matrices (which i've done) and the post multipy the matrices to get the result matrix. the matrix C was from point O to joint 1, matrix B is from joint 1 to joint 2, and matrix A is from joint 2 to point P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0HI THERE I KNOW IT TOOK ME A LONG TIME BUT I PROMISED SOMEONE TO FINISH THERE 50 QUESTIONS

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0syms cosx sinx asinx acosx cosy siny bcosy bsiny cosz sinz csinz ccosz syms cosx sinx asinx acosx cosy siny bcosy bsiny cosz sinz csinz ccosz A=[cosx, sinx,0, acosx;sinx,cosx,0,asinx;0,0,1,0;0,0,0,1]; B=[cosy, siny,0, bcosy;siny,cosy,0,bsiny;0,0,1,0;0,0,0,1]; %C=[cosz, sinz,0, ccosz;sinz,cosz,0,csinz;0,0,1,0;0,0,0,1]; %Linear algebraic product of the matrices... M1= A * B * C; M2= A*B; M3= B*C; M4= A*C; %Array arithmetic operations are carried out element by element M1= A * B * C; M2= A*B; M3= B*C; M4= A*C;

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the result for linear algebraic multiplication for example A x B

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A = [ cosx, sinx, 0, acosx] [ sinx, cosx, 0, asinx] [ 0, 0, 1, 0] [ 0, 0, 0, 1]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0B = [ cosy, siny, 0, bcosy] [ siny, cosy, 0, bsiny] [ 0, 0, 1, 0] [ 0, 0, 0, 1]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A*B ans = [ cosx*cosy  sinx*siny,  cosx*siny  cosy*sinx, 0, acosx + bcosy*cosx  bsiny*sinx] [ cosx*siny + cosy*sinx, cosx*cosy  sinx*siny, 0, asinx + bsiny*cosx + bcosy*sinx] [ 0, 0, 1, 0] [ 0, 0, 0, 1]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so this is what u called messy result which seems to be exclusive of your intuitive expectation, however the element by element matrix multiplication would give a result hopefully to your expectation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A.*B ans = [ cosx*cosy, sinx*siny, 0, acosx*bcosy] [ sinx*siny, cosx*cosy, 0, asinx*bsiny] [ 0, 0, 1, 0] [ 0, 0, 0, 1]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Array arithmetic operations are carried out element by element, and can be used with multidimensional arrays. The period character (.) distinguishes the array operations from the matrix operations.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry i was busy but i have to keep all my promises not matter what, so all the best and good luck.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now with this basic method you can do whatever multiplication you want, and in any associative, distributive ... way you want.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you, i think i will have to ask which multiplication is needed since i don't know. i would hope it's the easier one though!
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