anonymous
  • anonymous
find the derivative of y with respect to x, t or theta as appropriate. y= ln(cos(ln theta))
Calculus1
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
its very simple
anonymous
  • anonymous
please help me
anonymous
  • anonymous
-(1/cos(ln theta))*(sin(ln theta)*1/theta

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stamp
  • stamp
\[\frac{d(ln(cos(ln(\theta)))}{dx}\]
stamp
  • stamp
Should be dTheta
anonymous
  • anonymous
the answer is - (tan (ln theta))/ theta
anonymous
  • anonymous
i just dont no how to get to that
stamp
  • stamp
\[\frac{1}{cos(ln(\theta))}*-sin(ln(\theta))*\frac{1}{\theta}\]\[\frac{-sin(ln(\theta))}{cos(ln(\theta))}\frac{1}{\theta}\]\[=\frac{-tan(ln(\theta))}{\theta}\]Let me know if we need to go over anything.
anonymous
  • anonymous
thank you this explains it :)
stamp
  • stamp
Ok good luck in calculus
anonymous
  • anonymous
thank you its really hard. just trying to keep up. have a test coming up i just hope to pass it. thank you for ur help!
stamp
  • stamp
Sure thing. Private message me if you ever want to discuss more problems.
anonymous
  • anonymous
ok thank you!

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