Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Can someone help me solve this, I have no clue where to begin

Algebra
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

1 Attachment
write 4 new sequences and see if we can develop patterns or equations for them
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 4 9 16 25 36 49 64 81 100 121 144 might be easier to construct in excel :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

1 4 9 16 25 36 49 64 81 100 121 144 169 196 225 256 289 324 361 400 441 484 529 576 625 676 729 784 841 900 961 1024 1089 1156 1225 1296 1369 1444 1521 1600 1681 1764 1849 1936 2025 2116 2209 2304 2401 2500 2601 2704 2809 2916 3025 3136 3249 3364 3481 3600 3721 3844 3969 4096 4225 4356 4489 4624 im sure theres a way to develop an explicit equation for each column then run sum summation rules on them
the difference tiers of the first column produce an equation as: 1 + 24n + 16n(n-1); for n=0,1,2,3,...
it looks like the second one can be constructed as: -4(1+8n+4n(n-1))
we can also prolly expand these out and simplify them before crunching them further
the 4th column can be considered as: 16(1+3n+n(n-1)) and the 3rd as: -(9+40n+16n(n-2))
by adding that all together we get: 1 + 24n + 16n(n-1)-4(1+8n+4n(n-1)) -(9+40n+16n(n-2))+16(1+3n+n(n-1)) which the wolf says simplifies to 16n+4 so the question is: what is the summation of n=0 to 2010 of: 16n+4?
\[\sum_{a}^{b}(16n+4)\] \[\sum_{a}^{b}16n+\sum_{a}^{b}4\] \[16\sum_{a}^{b}n+4\sum_{a}^{b}\] \[16\frac{k(k+1)}{2}+4k\] where k is the number of elements
might have my numbers a little mixed about, but i think its good
I dont really understand fully,
how did you get the equation
Here's a different approach. Observe that the nth and the (n+1)th square differ by 2n + 1, as (n+1)^2 - n^2 = 2n + 1. For example 4 and 9 difference by 2x2 + 1 = 5 9 and 16 by 2x3 + 1 = 7 etc. Now, looking at the sequence you have, let's look at each group of four and write down an equation for it, starting with -4 -9 16 25 -4 and 16 differ by and add up to (2n + 1) + (2n + 3) = 4n + 4,where n = 2 -9 and 25 differ by and add up to (2(n+1) + 1) + (2(n+1) + 3) = 4n + 8 (n = 2) Hence -4 - 9 + 16 + 25 = 8n + 12 = 28 (n = 2) Now take this term 8n + 12 and generalize as needed for your problem.

Not the answer you are looking for?

Search for more explanations.

Ask your own question