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 one year ago
this is a question from a past math contest but I do not understand how we even get near to finding the ansnwe. Can some one please answer this step by step. Thanks =)
 one year ago
this is a question from a past math contest but I do not understand how we even get near to finding the ansnwe. Can some one please answer this step by step. Thanks =)

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KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.0So here's the way I looked at it. The pattern is simply \[n^2(n+1)^2(n+2)^2+(n+3)^2+...\]Starting at \(n=1\), and stopping as soon as we hit 2011. That expression simplifies as \[n^2(n+1)^2(n+2)^2+(n+3)^2=4.\]That's right. Just 4.

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.0Then, \(2011=502\cdot 4+3\). So we have 502 subsequences that look like \[n^2(n+1)^2(n+2)^2+(n+3)^2,\]and then we finish with \[2009^22010^22011^2.\]So the total sum would be\[502*4+2009^22010^22011^2=4046132\]which is choice E.
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