Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
this is a question from a past math contest but I do not understand how we even get near to finding the ansnwe. Can some one please answer this step by step. Thanks =)
 one year ago
 one year ago
this is a question from a past math contest but I do not understand how we even get near to finding the ansnwe. Can some one please answer this step by step. Thanks =)
 one year ago
 one year ago

This Question is Open

KingGeorgeBest ResponseYou've already chosen the best response.0
So here's the way I looked at it. The pattern is simply \[n^2(n+1)^2(n+2)^2+(n+3)^2+...\]Starting at \(n=1\), and stopping as soon as we hit 2011. That expression simplifies as \[n^2(n+1)^2(n+2)^2+(n+3)^2=4.\]That's right. Just 4.
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.0
Then, \(2011=502\cdot 4+3\). So we have 502 subsequences that look like \[n^2(n+1)^2(n+2)^2+(n+3)^2,\]and then we finish with \[2009^22010^22011^2.\]So the total sum would be\[502*4+2009^22010^22011^2=4046132\]which is choice E.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.