Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
General integration t^2 (t^3  3)^10 dt is the u sub = t^33? du/dt = 3t^2 du = 3t^2dx
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
du=3t^2dt, yah looks good so far. From here, you want to solve for `t^2dt`, so you can replace that part in your integral. So get the 3 off of it! :O
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
do you mean when you divide by 1/3?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
mutiply by 1/3, or divide by 3, yes.
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
i did 1/3 integral 3t^2 * t^2 (t^33)^10 dt and 3t^2 dt is du so 1/3 integral t^2 u^10 du?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large du=3t^2 dt \qquad \rightarrow \qquad \color{orangered}{\frac{1}{3}du=t^2dt}\]I would have changed the 1/3 in this step, but the way you did it works fine also! :) It looks like you replaced dt with du, you didn't replace the t^2 hmm
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Oh you have t^2 twice in there for some reason..? :O
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large \int \frac{1}{3}(t^33)^{10}\color{orangered}{3t^2\; dt}\]\[\large \color{orangered}{du=3t^2dt}\]
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
because the original equation has t^2 * (t^33)^10 dt
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
and u sub = 3t^2
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
So how did that change to, 1/3 integral 3t^2 * `t^2` (t^33)^10 dt? See how you have an extra t^2?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large \int\limits t^2(t^33)^{10}dt \qquad \rightarrow \qquad \frac{1}{3}\int\limits 3t^2(t^33)^{10}dt\]I understand what you were doing here, you put a 1/3 and 3 in to fix things up. But you also threw in a t^2! woops! :)
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
OH yea! i only put the 3! instead i put du there _
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
oh i see XD heh
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
oh ok so it's 1/3 integral 3t^2 (t^33)^10 dt 1/3 integral u^10 du?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
yes looks good!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.