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General integration t^2 (t^3 - 3)^10 dt
is the u sub = t^3-3?
du/dt = 3t^2
du = 3t^2dx

do you mean when you divide by 1/3?

mutiply by 1/3, or divide by 3, yes.

i did 1/3 integral 3t^2 * t^2 (t^3-3)^10 dt
and 3t^2 dt is du
so 1/3 integral t^2 u^10 du?

Oh you have t^2 twice in there for some reason..? :O

because the original equation has t^2 * (t^3-3)^10 dt

and u sub = 3t^2

So how did that change to, 1/3 integral 3t^2 * `t^2` (t^3-3)^10 dt?
See how you have an extra t^2?

OH yea! i only put the 3! instead i put du there -_-

oh i see XD heh

oh ok so it's 1/3 integral 3t^2 (t^3-3)^10 dt
1/3 integral u^10 du?

yes looks good!