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It turns out into a system of equations.

\[
8:4:x=c(2:y:6) \\
8 = 2c \\
4 = cy\\
x = 6c \\
\]

First solve for c, then solve for x and y.

where does the c come from?

The alphabet.

You need to find a c such that the above equation is true.

I know a/b = c/d and a*d=b*c but this euqstion had 3 terms which is confusing me

Have you solved for c?

umm.

im not sure how

\[
8=2c
\]

\[
\frac{8}{2} = \frac{4}{y} \\
\frac{8}{2} = \frac{x}{6}
\]

but how does 8 = 2c?

$$8=2c$$
$$\frac{1}{2}*8=\frac{1}{2}*2c$$
$$4=(\frac{1}{2}*2)c$$
$$4=1c$$
$$4=c$$

$$ 8:4:x = 2: y:6$$
$$8:4:x = c(2: y:6)$$

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