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Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0\[y ^{8}\] \[(2x+y^{2})^{6}\]

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0Would it turn out to be \[y ^{8}=(y ^{2})^{U}\]

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0My class hasn't covered logarithms yet, so I'm not sure if it's a guess 'n check type of thing.

Rogue
 2 years ago
Best ResponseYou've already chosen the best response.0Banging it out and multiplying will be extremely tedious. There's a simpler way to do it by using binomial theorem, but that is far too much explaining for now if you haven't already learned it. Does anyone have any other ideas?

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0I guess you could make an equation out of the exponents 8=2U...

robtobey
 2 years ago
Best ResponseYou've already chosen the best response.0\[\left(2 x+y^2\right)^6=64 x^6+192 x^5 y^2+240 x^4 y^4+160 x^3 y^6+60 x^2 y^8+12 x y^{10}+y^{12} \]
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