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Pologirl19

  • 3 years ago

Can someone please help me I am stuck... How do the graphs of y=1/x and y=5/x+6 compare?

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  1. stamp
    • 3 years ago
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    \[y_{1}=\frac{1}{x},\ y_{2}=\frac{5}{x+6}\]Can you visualize y1 or y2? If so, draw a sketch of the graph(s)

  2. stamp
    • 3 years ago
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    It might help to think of y2 as\[y_{2}=5(\frac{1}{x+6})\]

  3. Pologirl19
    • 3 years ago
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    What happened to the other x?|dw:1360212091432:dw|

  4. Pologirl19
    • 3 years ago
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    Thats what my graph is suppose to look like, but I need to know how they compare.

  5. blurbendy
    • 3 years ago
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    is the second one y = (5/x) +6 or y = (5) / (x+6) ?

  6. Pologirl19
    • 3 years ago
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    The second one

  7. ZakaullahUET
    • 3 years ago
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    |dw:1360212481953:dw|

  8. blurbendy
    • 3 years ago
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    I think you have the graphs for y = 1/x and y = (5/x) +6 not (5) / (x +6)

  9. ZakaullahUET
    • 3 years ago
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    |dw:1360212546332:dw|

  10. ZakaullahUET
    • 3 years ago
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    |dw:1360212588584:dw|

  11. Pologirl19
    • 3 years ago
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    It does not say on my graph

  12. ZakaullahUET
    • 3 years ago
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    |dw:1360212632344:dw|

  13. Pologirl19
    • 3 years ago
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    ^Thats the right graph but how do they compare

  14. ZakaullahUET
    • 3 years ago
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    i showed points on both the graphs when the +6 term comes the graph is moved to the left 6 steps

  15. ZakaullahUET
    • 3 years ago
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    |dw:1360213092724:dw|

  16. Pologirl19
    • 3 years ago
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    Oh okay

  17. Pologirl19
    • 3 years ago
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    Well it still doesnt make sense

  18. ZakaullahUET
    • 3 years ago
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    it does both are same things but the one graph is a little wide near the origin and u get y=5 for x=1

  19. ZakaullahUET
    • 3 years ago
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    and then it is moved to the left

  20. ZakaullahUET
    • 3 years ago
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    both are hyperbolas but only thats the difference

  21. Pologirl19
    • 3 years ago
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    well I need an equation

  22. ZakaullahUET
    • 3 years ago
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    u see the magniture of the function increased with multiplying by 5 and graph shifted to the left with the 6

  23. ZakaullahUET
    • 3 years ago
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    magnitude

  24. agent0smith
    • 3 years ago
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    For an equation to compare them... lets call them f1(x) and f2(x) \[f _{1}(x) = y _{1} =\frac{ 1 }{ x }\]\[ f_{2}(x) = y _{2} =\frac{ 5 }{ x+6 } = 5\left( \frac{ 1 }{ x+6 } \right)\]

  25. agent0smith
    • 3 years ago
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    \[f _{2}(x) =5 \times f _{1}(x+6)\]

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