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anonymous
 3 years ago
i neeeed serious help.....
anonymous
 3 years ago
i neeeed serious help.....

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do you need help with?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In the figure below, find the exact value of y. (Do not approximate your answer.)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i attached the problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0find the side of the larger triange, using pyth theorem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. It is a 45 45 90 triangle. So we know the hypotenuse is five. The hypotenuse in a 45 45 90 triangle is x(sqrt2). So sqrt2 is 1.41. 5/1.41 is 3.546. So x=3.546. Since it equals x.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1The three triangles are similar, so the lengths of their sides are proportional. 6/5 = 5/y

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1You don't know it's a 454590 triangle.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then the side that you found is the hypothenuse of 454590 triangle. using that hypotheneuse is twice as large as legs, find the size of the legs

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1If the altitude is drawn to the hypotenuse of a right triangle, each leg of the right triangle is the geometric mean of the hypotenuse and the segment of the hypotenuse adjacent to the leg.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0simple  use 454590 logic that y y  ysqrt2 5 = ysqrt2 solve for y

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1@JuanitaM Why do you keep mentioning a 454590 trianlge when we don't have one here?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes an altitude was droppened to form 90 degree at base labeled 6

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1The large triangle has hypotenuse of length 6 and a leg of length 5. The other leg cannot possibly measure 5, so it's not a 454590 triangle. Since all triangles are similar, none of them are 454590 triangles.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Find the 3rd side of the triangle, label this x. \[x=\sqrt{6^25^2}=\sqrt{11}\] Then find the line going straight down the triangle, label this z. You can do this two ways (you'll need both ways). \[z=\sqrt{\sqrt{11}^2(6y)^2}=\sqrt{11(6y)^2}\] \[z=\sqrt{5^2y^2}\] If you make them equal to each other, you'll be able to solve for y. \[\sqrt{11(6y)^2}=\sqrt{5^2y^2}\] \[11(6y)^2=25y^2\] \[11(3612y+y^2)=25y^2\] \[2y^212y50=0\] \[\therefore y=\sqrt{34}+3\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is this too confusing?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360214471836:dw Maybe that will make it more understandable :)

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1@Chelsea04 Can you try to calculate your answer for y as a number rounded off to the nearest tenth?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1@yanni Did you understand anything about this problem or are you more confused than when you asked the question?

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2Chelsea, your answer cannot be correct. Your value of y is greater than the 6 at the base of the triangle!

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2Chelsea, this is your mistake: \[11−(36−12y+y^2)=25−y^2\]\[12y−50=0 \] mathstudent55 has the correct answer: The three triangles are similar, so the lengths of their sides are proportional. 6/5 = 5/y You can confirm it by using cosine.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1@agent0smith Finally a voice of reason. Thanks!

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2haha no prob. I forgot to make the drawing:

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2I'll call that angle x dw:1360216763172:dw First, look at the bigger/outer triangle \[\cos x = \frac{ 5 }{ 6 }\] Now, look at the inner triangle: \[\cos x = \frac{ y }{ 5 }\] dw:1360216959551:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Right, oops!!! That seems like a much faster way!!!

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2once you get cosx = 5/6 and cos x = y/5, then you can equate 5/6 = y/5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Either way is correct, just mine was more algebraic (and a little wrong!) than trignometric.

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.2Yes, your way works (other than your mistake) but will probably take longer.
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