## ammu123 Group Title Find the derivative of y with respect to x, t, or θ, as appropriate y = ln (cos (ln θ)) the answer is -(tan (lnθ)/θ) i just dont know how to get that one year ago one year ago

So this is just a multiple chain rule so it becomes $\ln(v(u))$$v = \cos(u)$ $u = \ln$ so you get $(1/\cos(\ln \theta) )* (-\sin(\ln \theta) * (1/\theta)$ $= -\tan(\ln \theta)/\theta$