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ammu123
 3 years ago
Find the derivative of y with respect to x, t, or θ, as appropriate
y = ln (cos (ln θ))
the answer is (tan (lnθ)/θ)
i just dont know how to get that
ammu123
 3 years ago
Find the derivative of y with respect to x, t, or θ, as appropriate y = ln (cos (ln θ)) the answer is (tan (lnθ)/θ) i just dont know how to get that

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azolotor
 3 years ago
Best ResponseYou've already chosen the best response.1So this is just a multiple chain rule so it becomes \[\ln(v(u))\]\[v = \cos(u)\] \[u = \ln\] so you get \[(1/\cos(\ln \theta) )* (\sin(\ln \theta) * (1/\theta)\] \[= \tan(\ln \theta)/\theta \]
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