anonymous
  • anonymous
Need help please? ( Picture attached below )
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
@Swin2013
anonymous
  • anonymous
I'm not sure how to approach this problem lol

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anonymous
  • anonymous
Try setting up a ratio
anonymous
  • anonymous
of the lengths
jim_thompson5910
  • jim_thompson5910
Hint: CD/BC = BC/AC
anonymous
  • anonymous
^yess BC/DC is very similar to CA/CB fill in the lengths you already know in this case, you know CA AND CB
anonymous
  • anonymous
That's 3 of your lengths! :)
anonymous
  • anonymous
Give me a sec lol
anonymous
  • anonymous
Alright I got it correct thanks for the help guys!
anonymous
  • anonymous
you're welcome!
anonymous
  • anonymous
\[\text{Round}\left[37*\text{Tan}\left[\frac{\pi }{2}-\text{ArcTan}\left[\frac{53}{37}\right]\right],0.01\right]=25.83 \]

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