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What don't you understand?
add 1 to each of the factors
so you have
(1+2) + (1+2)
You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha
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you multiply, not add, but the same idea yes.
so if the equation is
then what you'd end up with, after distribution is
@Profunds77 $$4( 90 + 12) = 4*90 + 4*12$$ Note 4 distributes as a MULTIPLIER of each term of the sum 90 + 12.
what he said
I like using letters instead :)
I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply
FOIL as in:
Are you taliking about that foil method?
FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property.
\[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\]
\[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.
Of course, if you prefer, this is equally valid:
\[(a+b)(c+d) = ac + bc + ad + bd\]
Whatever method gets you through it systematically and correctly....