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Profunds77

  • one year ago

Can someone explain the distributive rule?

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  1. skullpatrol
    • one year ago
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    What don't you understand?

  2. rebeccaskell94
    • one year ago
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    Sure! basically 1(2+2) add 1 to each of the factors so you have (1+2) + (1+2) You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha

  3. skullpatrol
    • one year ago
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    That^ is NOT right at all

  4. Chelsea04
    • one year ago
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    you multiply, not add, but the same idea yes.

  5. Chelsea04
    • one year ago
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    so if the equation is x(a+b) then what you'd end up with, after distribution is ax+bx

  6. skullpatrol
    • one year ago
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    @Profunds77 $$4( 90 + 12) = 4*90 + 4*12$$ Note 4 distributes as a MULTIPLIER of each term of the sum 90 + 12.

  7. Chelsea04
    • one year ago
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    what he said

  8. Chelsea04
    • one year ago
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    I like using letters instead :)

  9. Profunds77
    • one year ago
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    I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply

  10. Profunds77
    • one year ago
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    Thanks

  11. Chelsea04
    • one year ago
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    FOIL as in: First Outside Inside Last Are you taliking about that foil method?

  12. Profunds77
    • one year ago
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    Yes

  13. whpalmer4
    • one year ago
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    FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property. \[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\] Compare with \[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.

  14. whpalmer4
    • one year ago
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    Of course, if you prefer, this is equally valid: \[(a+b)(c+d) = ac + bc + ad + bd\] Whatever method gets you through it systematically and correctly....

  15. UnkleRhaukus
    • one year ago
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    \[A\star(B+ C)=A\star B+ A\star C\]

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