A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0What don't you understand?

rebeccaskell94
 2 years ago
Best ResponseYou've already chosen the best response.0Sure! basically 1(2+2) add 1 to each of the factors so you have (1+2) + (1+2) You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0That^ is NOT right at all

Chelsea04
 2 years ago
Best ResponseYou've already chosen the best response.0you multiply, not add, but the same idea yes.

Chelsea04
 2 years ago
Best ResponseYou've already chosen the best response.0so if the equation is x(a+b) then what you'd end up with, after distribution is ax+bx

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0@Profunds77 $$4( 90 + 12) = 4*90 + 4*12$$ Note 4 distributes as a MULTIPLIER of each term of the sum 90 + 12.

Chelsea04
 2 years ago
Best ResponseYou've already chosen the best response.0I like using letters instead :)

Profunds77
 2 years ago
Best ResponseYou've already chosen the best response.0I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply

Chelsea04
 2 years ago
Best ResponseYou've already chosen the best response.0FOIL as in: First Outside Inside Last Are you taliking about that foil method?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property. \[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\] Compare with \[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Of course, if you prefer, this is equally valid: \[(a+b)(c+d) = ac + bc + ad + bd\] Whatever method gets you through it systematically and correctly....

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[A\star(B+ C)=A\star B+ A\star C\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.