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Profunds77 Group Title

Can someone explain the distributive rule?

  • one year ago
  • one year ago

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  1. skullpatrol Group Title
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    What don't you understand?

    • one year ago
  2. rebeccaskell94 Group Title
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    Sure! basically 1(2+2) add 1 to each of the factors so you have (1+2) + (1+2) You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha

    • one year ago
  3. skullpatrol Group Title
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    That^ is NOT right at all

    • one year ago
  4. Chelsea04 Group Title
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    you multiply, not add, but the same idea yes.

    • one year ago
  5. Chelsea04 Group Title
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    so if the equation is x(a+b) then what you'd end up with, after distribution is ax+bx

    • one year ago
  6. skullpatrol Group Title
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    @Profunds77 $$4( 90 + 12) = 4*90 + 4*12$$ Note 4 distributes as a MULTIPLIER of each term of the sum 90 + 12.

    • one year ago
  7. Chelsea04 Group Title
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    what he said

    • one year ago
  8. Chelsea04 Group Title
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    I like using letters instead :)

    • one year ago
  9. Profunds77 Group Title
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    I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply

    • one year ago
  10. Profunds77 Group Title
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    Thanks

    • one year ago
  11. Chelsea04 Group Title
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    FOIL as in: First Outside Inside Last Are you taliking about that foil method?

    • one year ago
  12. Profunds77 Group Title
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    Yes

    • one year ago
  13. whpalmer4 Group Title
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    FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property. \[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\] Compare with \[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.

    • one year ago
  14. whpalmer4 Group Title
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    Of course, if you prefer, this is equally valid: \[(a+b)(c+d) = ac + bc + ad + bd\] Whatever method gets you through it systematically and correctly....

    • one year ago
  15. UnkleRhaukus Group Title
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    \[A\star(B+ C)=A\star B+ A\star C\]

    • one year ago
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