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anonymous
 3 years ago
Can someone explain the distributive rule?
anonymous
 3 years ago
Can someone explain the distributive rule?

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skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.0What don't you understand?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sure! basically 1(2+2) add 1 to each of the factors so you have (1+2) + (1+2) You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.0That^ is NOT right at all

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you multiply, not add, but the same idea yes.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if the equation is x(a+b) then what you'd end up with, after distribution is ax+bx

skullpatrol
 3 years ago
Best ResponseYou've already chosen the best response.0@Profunds77 $$4( 90 + 12) = 4*90 + 4*12$$ Note 4 distributes as a MULTIPLIER of each term of the sum 90 + 12.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I like using letters instead :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0FOIL as in: First Outside Inside Last Are you taliking about that foil method?

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property. \[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\] Compare with \[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1Of course, if you prefer, this is equally valid: \[(a+b)(c+d) = ac + bc + ad + bd\] Whatever method gets you through it systematically and correctly....

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\[A\star(B+ C)=A\star B+ A\star C\]
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