At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
What don't you understand?
Sure! basically 1(2+2) add 1 to each of the factors so you have (1+2) + (1+2) You distribute the outsider to each of the insiders. and it's not lonely anymore c: xD haha
That^ is NOT right at all
you multiply, not add, but the same idea yes.
so if the equation is x(a+b) then what you'd end up with, after distribution is ax+bx
what he said
I like using letters instead :)
I was looking at a question answered and they mentioned the distributive rule instead of the foil method just looking for new technics that I can apply
FOIL as in: First Outside Inside Last Are you taliking about that foil method?
FOIL is just a memory crutch to keep the work organized, but you're doing the distributive property. \[(a + b)(c + d) = a(c+d) + b(c + d) = ac + ad + bc + bd\] Compare with \[(a+b)(c+d) = ac + ad + bc + bd\]Same thing.
Of course, if you prefer, this is equally valid: \[(a+b)(c+d) = ac + bc + ad + bd\] Whatever method gets you through it systematically and correctly....
\[A\star(B+ C)=A\star B+ A\star C\]