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clhenry Group Title

Find the value of $10000 at the end of one year if it is invested in an account that has an interest rate of 4.95% and is compounded in accordance with the rules below. (a). compounded monthly (b). compounded daily (assuming a 365- day year) (c). compounded quarterly

  • one year ago
  • one year ago

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  1. PhoenixFire Group Title
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    Do you know the compound interest formula?

    • one year ago
  2. PhoenixFire Group Title
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    \[F=P(1+{r \over n})^{nt}\]F=Future amount P=Initial amount r=annual interest rate n=number of times compounded in a year t=number of years. So, for (a), compounded monthly. n=12, t=1, P=10000, r=0.0495. Substitute all that in and you'll have your F, the future amount.

    • one year ago
  3. clhenry Group Title
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    Actually they are giving me the formula A=P(1+r/m)mt

    • one year ago
  4. clhenry Group Title
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    \[10000(1+0.0495\div12)12\]

    • one year ago
  5. PhoenixFire Group Title
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    Same thing, different letters.

    • one year ago
  6. clhenry Group Title
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    ok. SO HOW CAN I FIND THE ANSWER BECAUSE WHAT IM GETTING DOESNT SEEM CORRECT TO WHAT THE EXAMPLE IS SHOWING ME

    • one year ago
  7. clhenry Group Title
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    I pretty much have found the computing formula to find each steps but unable to get verifiable answer

    • one year ago
  8. clhenry Group Title
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    because in the examples they use 15000 and the answer turns out to be $15696.91

    • one year ago
  9. PhoenixFire Group Title
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    \[A=P(1+{r \over m})^{mt}\]\[A=10000(1+{0.0495\over 12})^{12}\]\[A=10000(1.05)\]\[A=10506.4\] Obviously I've done rounding where I shouldn't have, but that's the procedure.

    • one year ago
  10. clhenry Group Title
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    how did they get that answers from using the formula because i know for m- i would put 12

    • one year ago
  11. PhoenixFire Group Title
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    What are the values they use in the examples?

    • one year ago
  12. clhenry Group Title
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    they used 15000-p, 0.0455- r, and 12- m

    • one year ago
  13. PhoenixFire Group Title
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    Right so, put those values in in the formula. \[A=15000(1+{0.0455\over 12})^{12}\]

    • one year ago
  14. clhenry Group Title
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    yes

    • one year ago
  15. PhoenixFire Group Title
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    And you get: 15696.91

    • one year ago
  16. clhenry Group Title
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    yes thats what they got

    • one year ago
  17. clhenry Group Title
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    how did u reach to that?

    • one year ago
  18. PhoenixFire Group Title
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    By working out the above equation. Lets do it step by step... Upcoming Ugly numbers!!! 0.0455/12=0.00379166666666666666666666666667 That+1=1.00379166666666666666666666666667 that ^ 12=1.0464609601126369220378253015612 that * 15000=15696.914401689553830567379523418 with some rounding, you get 15696.91.

    • one year ago
  19. clhenry Group Title
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    thank you

    • one year ago
  20. clhenry Group Title
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    let me try it myself and i will let you know

    • one year ago
  21. PhoenixFire Group Title
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    Order of operations. Brackets Exponents Division Multiplication Addition Subtraction or easily remembering: BEDMAS. Also, remember ab^k is NOT equal (ab)^k. the difference is that ab^k is a*(b^k) whereas (ab)^k is (a*b) ^ k... there's a different order that you apply the maths in; which result in a different value at the end.

    • one year ago
  22. clhenry Group Title
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    ok

    • one year ago
  23. PhoenixFire Group Title
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    Good luck.

    • one year ago
  24. clhenry Group Title
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    it didnt work the way u did it when i plugged everything myself into the equation It give me 10,506.39 and i got 2690666.1

    • one year ago
  25. PhoenixFire Group Title
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    Work it out in steps. 0.0495/12=a 1+a=b b^12=c P*c=F

    • one year ago
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