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DEEBA

A box has 8 hard centred and 9 soft centred chocolates. two are selected at random.what is the probability that one is hard centred and other is soft centred

  • one year ago
  • one year ago

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  1. Chelsea04
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    1/8*1/9 so 1/72

    • one year ago
  2. Chelsea04
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    you find the probability of getting a hard centred: 1/8 then the probability of getting a soft centred: 1/9 then multiply them together

    • one year ago
  3. Chelsea04
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    it's wrong isn't it

    • one year ago
  4. agent0smith
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    I think you may have to double your answer @Chelsea04 as you could get one hard, then one soft, or one soft, then one hard.

    • one year ago
  5. Chelsea04
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    i'm thinking of a different question. oh, right, yea. that i think makes much more sense

    • one year ago
  6. Chelsea04
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    no! no! I got it now! hard centred: 8/17 soft centred: 9/17 multiply these together 72/289

    • one year ago
  7. agent0smith
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    Yeah that sounds a bit better... been a while since i've done one of these.

    • one year ago
  8. Chelsea04
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    do you multiply that by 2?

    • one year ago
  9. Chelsea04
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    yea, me too! been like 3 months

    • one year ago
  10. agent0smith
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    Hmm i'm not sure if that's correct. It may be easier to do it using combinations...

    • one year ago
  11. Chelsea04
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    use a tree diagram, i'll draw one

    • one year ago
  12. agent0smith
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    There's four possible outcomes: (h, h), (s,s), (h,s), (s,h)

    • one year ago
  13. agent0smith
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    (note not all are equally likely as there's 8 hard and 9 soft)

    • one year ago
  14. agent0smith
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    \[\left(\frac{ 8 }{ 17 } \times \frac{ 9 }{ 16 }\right) + \left(\frac{ 9 }{ 17 } \times \frac{ 8 }{ 16 }\right) \] I think this covers all possibilities...

    • one year ago
  15. Chelsea04
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    yea, it does

    • one year ago
  16. Chelsea04
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    so basically in the end, you did need to multiply it by 2 ;)

    • one year ago
  17. agent0smith
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    Yep, but your original equation had them both over 17, not one over 17 and one over 16.

    • one year ago
  18. Chelsea04
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    right, no replacement! Sorry, it's been a while

    • one year ago
  19. DEEBA
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    is it the rite ans

    • one year ago
  20. Chelsea04
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    agent's is the right answer, follow his equation

    • one year ago
  21. agent0smith
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    \[\left(\frac{ 8 }{ 17 } \times \frac{ 9 }{ 16 }\right) + \left(\frac{ 9 }{ 17 } \times \frac{ 8 }{ 16 }\right) = 2 \times \left(\frac{ 9 \times 8 }{ 17 \times 16 } \right) = 0.529\] So the probability is about 50%, which makes sense given our possible outcomes when picking two chocolates (h for hard, s for soft): (h, h), (s,s), (h,s), (s,h) If all options were equally likely, the probability would be exactly 50%.

    • one year ago
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