At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

I know how to find it about point A, but I am having difficulty seeing how to find it for point B.

Seperately Solve the hinge forces...:)

I don't understand what you mean.

I'll do it then.
What is the definition of the moment of a force?

The moment of a force is its ability to create rotation.

Yes, but mathematically and precisely, with a formula?

M = F*d, where d is the distance between the point of application and the pivot

or M = r x F

(btw thanks for your help, I have been lost for hours)

Yes. Now, let's start with F3. What's the moment due to that force?

ah!! that's what I thought! but I thought it would be wrong bcs it was 0

Now, what about F2?

bcs the position vector at B is <0,0,0> and crossing it with the F3 vector would give zero.

yes

ahh i see

yes

yes

awesome.

for f2. I think it goes like this:

the position vector would be : <-3, 4 , 0>

No, you want the positive vector RELATIVE TO B

Which will be just r = <0,4,0>

hmmm would not that be moving to the right of B and up from B?

oh yes! sorry I was doing F1 mistakenly !

oh right. yes, F2. Doing them backwards because F1 is the most complicated.

r = <0, 4 0 > ; F2 = < -300*sin(60) , -300 *cos(60) , 0 >

check your sin and cos there

ah, i see that I did. I was putting it on the wrong side

< -300*cos(60) , -300 *sin(60) , 0 >

Yes.
Ok, you've got it. I'll leave you with F1 now by yourself.

I have dyslexia and its hard to see things sometimes! Thanks for your patience

for F1, r = < -3 , 4 , 0 >

yes

F1 = < 250*sin(30) , -250*cos(3), 0 >

r x F1 = 149.519

Looks right (30 obviously). Now calculate the cross products

r2 x f2 = 600