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I know how to find it about point A, but I am having difficulty seeing how to find it for point B.

Seperately Solve the hinge forces...:)

I don't understand what you mean.

I'll do it then.
What is the definition of the moment of a force?

The moment of a force is its ability to create rotation.

Yes, but mathematically and precisely, with a formula?

M = F*d, where d is the distance between the point of application and the pivot

or M = r x F

(btw thanks for your help, I have been lost for hours)

Yes. Now, let's start with F3. What's the moment due to that force?

ah!! that's what I thought! but I thought it would be wrong bcs it was 0

Now, what about F2?

bcs the position vector at B is <0,0,0> and crossing it with the F3 vector would give zero.

yes

ahh i see

yes

yes

awesome.

for f2. I think it goes like this:

the position vector would be : <-3, 4 , 0>

No, you want the positive vector RELATIVE TO B

Which will be just r = <0,4,0>

hmmm would not that be moving to the right of B and up from B?

oh yes! sorry I was doing F1 mistakenly !

oh right. yes, F2. Doing them backwards because F1 is the most complicated.

r = <0, 4 0 > ; F2 = < -300*sin(60) , -300 *cos(60) , 0 >

check your sin and cos there

ah, i see that I did. I was putting it on the wrong side

< -300*cos(60) , -300 *sin(60) , 0 >

Yes.
Ok, you've got it. I'll leave you with F1 now by yourself.

I have dyslexia and its hard to see things sometimes! Thanks for your patience

for F1, r = < -3 , 4 , 0 >

yes

F1 = < 250*sin(30) , -250*cos(3), 0 >

r x F1 = 149.519

Looks right (30 obviously). Now calculate the cross products

r2 x f2 = 600