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TuringTestBest ResponseYou've already chosen the best response.0
\[\large\int\frac12t2^{\frac12e^t}dt\]This?
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
No, the first t is in bottom with the 2, and the second 2 is under a radical by itself and e^t is another variable not an entire exponent
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
\[\Large \int \frac{1}{2t}dt 2^{1/2} \int e^t dt\] If that's not what you mean I suggest you, trying to \( \LaTeX\) it out yourself, so we all talk about the same problem.
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
It's almost right just include e^t after the square root of 2 and take off dt till the end
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
\[\int\limits_{\infty}^{\infty}[\frac{ 1 }{ 2t }\sqrt{2}e^t]dt\]
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
is that your question?
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
@Spacelimbus is right you need to tell him the right question so he can help you to provide you with the right solution.
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
\[\int\limits[\frac{ 1 }{ 2t }\sqrt{2}e^t]dt\]
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
sorry this is an indefinite integral i think you are asking
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
if this is the right question then the answer would be
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
\[=\frac{ 1 }{ 2 }\ln(t)2^\frac{ 1 }{2 } e^t+c\]
 one year ago

mathsmindBest ResponseYou've already chosen the best response.1
otherwise help us to help you by providing the right question
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
Yes that's the right question! But how you solve it?
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
Forget it, I got it, thank you
 one year ago
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