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aprilanahi

  • 2 years ago

Find the indefinite integral of ((1/2t)-(2)^(1/2)e^t)dt

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  1. TuringTest
    • 2 years ago
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    \[\large\int\frac12t-2^{\frac12e^t}dt\]This?

  2. aprilanahi
    • 2 years ago
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    No, the first t is in bottom with the 2, and the second 2 is under a radical by itself and e^t is another variable not an entire exponent

  3. Spacelimbus
    • 2 years ago
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    \[\Large \int \frac{1}{2t}dt- 2^{1/2} \int e^t dt\] If that's not what you mean I suggest you, trying to \( \LaTeX\) it out yourself, so we all talk about the same problem.

  4. aprilanahi
    • 2 years ago
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    It's almost right just include e^t after the square root of 2 and take off dt till the end

  5. mathsmind
    • 2 years ago
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    \[\int\limits_{-\infty}^{\infty}[\frac{ 1 }{ 2t }-\sqrt{2}e^t]dt\]

  6. mathsmind
    • 2 years ago
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    is that your question?

  7. mathsmind
    • 2 years ago
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    @Spacelimbus is right you need to tell him the right question so he can help you to provide you with the right solution.

  8. mathsmind
    • 2 years ago
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    \[\int\limits[\frac{ 1 }{ 2t }-\sqrt{2}e^t]dt\]

  9. mathsmind
    • 2 years ago
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    sorry this is an indefinite integral i think you are asking

  10. mathsmind
    • 2 years ago
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    if this is the right question then the answer would be

  11. mathsmind
    • 2 years ago
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    \[=\frac{ 1 }{ 2 }\ln(t)-2^\frac{ 1 }{2 } e^t+c\]

  12. mathsmind
    • 2 years ago
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    otherwise help us to help you by providing the right question

  13. aprilanahi
    • 2 years ago
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    Yes that's the right question! But how you solve it?

  14. aprilanahi
    • 2 years ago
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    Forget it, I got it, thank you

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