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TuringTest
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\int\frac12t2^{\frac12e^t}dt\]This?

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0No, the first t is in bottom with the 2, and the second 2 is under a radical by itself and e^t is another variable not an entire exponent

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.0\[\Large \int \frac{1}{2t}dt 2^{1/2} \int e^t dt\] If that's not what you mean I suggest you, trying to \( \LaTeX\) it out yourself, so we all talk about the same problem.

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0It's almost right just include e^t after the square root of 2 and take off dt till the end

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{\infty}^{\infty}[\frac{ 1 }{ 2t }\sqrt{2}e^t]dt\]

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1is that your question?

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1@Spacelimbus is right you need to tell him the right question so he can help you to provide you with the right solution.

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits[\frac{ 1 }{ 2t }\sqrt{2}e^t]dt\]

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1sorry this is an indefinite integral i think you are asking

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1if this is the right question then the answer would be

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1\[=\frac{ 1 }{ 2 }\ln(t)2^\frac{ 1 }{2 } e^t+c\]

mathsmind
 one year ago
Best ResponseYou've already chosen the best response.1otherwise help us to help you by providing the right question

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0Yes that's the right question! But how you solve it?

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0Forget it, I got it, thank you
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