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JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3Hint: what's the derivative with respect to y of cot(y) ?

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3No. But it is related to the 1/sin^2 y in your question

aprilanahi
 2 years ago
Best ResponseYou've already chosen the best response.0I still don't get it?

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3\[ \frac{d }{dy} \cot y =  \frac{1}{\sin^2 y} =  \csc^2 y \]

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3Hence \[ \int \left( y + \frac{2}{\sin^2 y} \right) \ dy = \int y \ dy + 2 \int \csc^2 y \ dy = ... \]

aprilanahi
 2 years ago
Best ResponseYou've already chosen the best response.0So what's the answer?

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3You tell me. I've done the first few steps for you. You only have 2 more to do: evaluate each of those integrals above

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3Double check your signs!
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