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JamesJBest ResponseYou've already chosen the best response.3
Hint: what's the derivative with respect to y of cot(y) ?
 one year ago

JamesJBest ResponseYou've already chosen the best response.3
No. But it is related to the 1/sin^2 y in your question
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
I still don't get it?
 one year ago

JamesJBest ResponseYou've already chosen the best response.3
\[ \frac{d }{dy} \cot y =  \frac{1}{\sin^2 y} =  \csc^2 y \]
 one year ago

JamesJBest ResponseYou've already chosen the best response.3
Hence \[ \int \left( y + \frac{2}{\sin^2 y} \right) \ dy = \int y \ dy + 2 \int \csc^2 y \ dy = ... \]
 one year ago

aprilanahiBest ResponseYou've already chosen the best response.0
So what's the answer?
 one year ago

JamesJBest ResponseYou've already chosen the best response.3
You tell me. I've done the first few steps for you. You only have 2 more to do: evaluate each of those integrals above
 one year ago

JamesJBest ResponseYou've already chosen the best response.3
Double check your signs!
 one year ago
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