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JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3Hint: what's the derivative with respect to y of cot(y) ?

JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3No. But it is related to the 1/sin^2 y in your question

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0I still don't get it?

JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3\[ \frac{d }{dy} \cot y =  \frac{1}{\sin^2 y} =  \csc^2 y \]

JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3Hence \[ \int \left( y + \frac{2}{\sin^2 y} \right) \ dy = \int y \ dy + 2 \int \csc^2 y \ dy = ... \]

aprilanahi
 one year ago
Best ResponseYou've already chosen the best response.0So what's the answer?

JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3You tell me. I've done the first few steps for you. You only have 2 more to do: evaluate each of those integrals above

JamesJ
 one year ago
Best ResponseYou've already chosen the best response.3Double check your signs!
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