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cali2

  • 3 years ago

Limits! Evaluate using the squeeze theorem. lim x^2 cos 1/x x->0 Help!! I have a lot of these to do so details would be uber helpful

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  1. TuringTest
    • 3 years ago
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    \(\cos\theta\) is always between -1 and 1, regardless of what \(\theta\) is. This means that\[x^2\le |x^2\cos\theta|\]

  2. TuringTest
    • 3 years ago
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    sorry, I meant that\[|x^2\cos\theta|\le x^2\]

  3. TuringTest
    • 3 years ago
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    therefore we can write\[-x^2\le x^2\cos(\frac1x)\le x^2\]

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