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The number of customers that visit a local small business is 29,600 and has been continuously declining at a rate of 2.9% each year. What is the approximate number of customers that visit the business in 10 years?
Identify the formula you will be using to solve this problem and post it here. We can move on from there.
A=Pe^-rt

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Other answers:

P=26600 r=0.029 t=10 i did it several times and get stuck help?
A is going to be the amount remaining, and it will be our variable. The equation is already solved for A, which is good. You say that you are getting stuck, so I assume that you have an answer to this problem to serve as reference?
can you show me all the steps with the answer so i can check my work please ?
I do not know the answer exactly, your variables seem accurate. Perhaps you evaluating it wrong, seeing as your setup is correct. Also, please be patient in waiting for replies because I am operating on a slower internet connection but I am working to help you as fast as I can.
22,149 21,874 39,558 22,054
I obtained 22,148.6 people
I would go with A. What answer were you obtaining so we can identify your error?
can you show me hoe you got 22148.6?
how^?
A=Pe^-rt P=26600 r=0.029 t=10 A = amount remaining after t time. -r is your rate of decay, and since our population is decreasing, we have -r. t is the time your rate of decay is applied for. Make sure that r and t are the same unit; since t is years and r is %/year, we are ok to start evaluating. \[A=Pe^{-rt}\]\[A=29,660e^{-(0.029)(10)}\]\[A=22,148.6=22,149\]Make sure that you are able to put this into your calculator accurately and obtain the proper answer.
oh OMGGGG i was putting 2660 instead of 29660 thanks
Yeah I was making that mistake too. Your original post has 29,600 as the value, but you listed 26,600 a few times. Good thing we found the error.
can you check this one ^^^^
is this right? The yearly attendance at a local movie theater is 68,000 and grows continuously at a rate of 3.5% each year. What is the approximate attendance at the movie theater in eight years? 89,973
\[A=Pe^{rt}\]\[A=68,000e^{0.035(8)}\]\[A=89,972.8\]\[A=89,973\]
thanks
np, I hope your classes go well. private message me if you ever want to study other problems in the future.

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